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dalvyx [7]
3 years ago
12

If m a= 15 and m cd= 55, then m ge = ? Photo attached need help ASAP

Mathematics
2 answers:
ad-work [718]3 years ago
4 0

Answer:

The measure of arc GE is 25°

Lisa [10]3 years ago
3 0

Answer:

The measure of arc GE is 25\°

Step-by-step explanation:

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

In this problem

m<A is a external angle

so

m

substitute the values and solve for the measure of arc GE

15\°=\frac{1}{2}(55\°-arc\ GE)

30\°=(55\°-arc\ GE)

arc\ GE=55\°-30\°=25\°

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Sara’s hair was 25 inches long. Three years later it was 43 inches long. What was the percent increase rounded to the nearest hu
Karo-lina-s [1.5K]

Answer:

Increase Percentage =

                               \frac{increase}{original} * 100= \frac{43-25}{25} *100= \frac{18}{25}*100 = 72

Percentage increase in hairlength = 72%

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3 years ago
Harris has two pipes to fill his aquarium. Pipe A can fill the aquarium at the rate of 4 gallons per minute. Pipe B can fill the
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3 years ago
PLEASE SOMEONE WHO IS SMART ANSWER THIS QUESTION
Daniel [21]

Answer:

36/32 or 1 1/8 (same thing)

Step-by-step explanation:

9 gallon / 32 quarts

First, you have to convert 9 gallon to quarts to match the denominator. In the table, it says that 1 gallon = 4 quarts, so you have to do, 9 x 4 which gives you 36. Now that the fraction is in the same form of units, 36 quarts / 32 quarts, you will have to write it as a mix fraction or you can just leave it as 36 quarts / 32 quarts. If you want it in mix fraction, it is 1 1/8.

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3 years ago
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3 years ago
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100μ=100 and a standard deviation sigma
Ksivusya [100]

Answer:

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 114, \sigma = 86

Find the probability that a randomly selected adult has an IQ between 86 and 114.

Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So

X = 114

Z = \frac{X - \mu}{\sigma}

Z = \frac{114 - 100}{20}

Z = 0.7

Z = 0.7 has a pvalue of 0.7580

X = 86

Z = \frac{X - \mu}{\sigma}

Z = \frac{86 - 100}{20}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420

0.7580 - 0.2420 = 0.5160

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

3 0
4 years ago
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