Find how many eighths you need to make 3 fourths.

A trinidadian who is planning to visit Canada changed $3192 to canadian currency. How many $ did the triodion received

DanielleElmas [232]

Answer:

$3934

Step-by-step explanation:

We know that the currency of different countries are different.

So, one US dollar = 1.23 Canadian dollar

Given : $3192

A trinidadian changed some US dollar to Canadian dollar who plans to visit Canada.

He exchanged $3192.

Therefore,

1 US dollar = 1.23 Canadian dollar

The value of $ 3192 will be equal to = 1.23 x 3192

= $ 3933.96

≈ $ 3934

Therefore, triodion received = $ 3934.

8 0

3 years ago

To convert degrees Fahrenheit (F) into degrees Celsius (C) use the formula 2003-05-04-00-00_files/i0150000.jpg. Rewrite the equa

mihalych1998 [28]

To covert degrees Fahrenheit (F) to degrees Celsius (C) we use the equation C = (F - 32) × 5/9 . To convert degrees Celsius (C) to degrees Fahrenheit (F) we have to rewrite the equation.
First step: Divide both sides by 5/9. The equation would look like this:
C(9/5) = (F - 32)

Second step: Add 32 on both sides.
32 + (9/5)C = F or F = 32 + (9/5)C

6 0

3 years ago

Determine the sample size needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and

WINSTONCH [101]

Answer:

n=170

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.65$ estimated proportion.

$p$ true population

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: