3 years ago

PLEASE HELP!!!!!

2 answers:

6 0

X = 25 x Cos(18 deg)

3 0

Your answer is: 23.78

(cm is the units, but the question said do not use units, but just in case you need it later on.)

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faltersainse [42]

2(wl+hl+hw)=2·(6·4.5+12·4.5+12·6)=306

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lozanna [386]

The answer is 2800 black shoes

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Illusion [34]

206.
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3 years ago

andrezito [222]

Answer:

The answer is the last one

$tan(x_{1}+x_{2}+x_{3})=\frac{tanx_{1}+tan(x_{2}+x_{3})}{1-tanx_{1}tan(x_{2}+x_{3})}$

Step-by-step explanation:

∵ $tan(x_{1}+x_{2}+x_{3}=\frac{tanx_{1}+tan(x_{2}+x_{3})}{1-tanx_{1}tan(x_{2}+x_{3})}$

$=\frac{tanx_{1}+\frac{tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}} }{1-tanx_{1}(\frac{tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}})}$

Multiply up and down by $1-tanx_{2}tanx_{3}$

$\frac{tanx_{1}(1-tanx_{2}tanx_{3})+tanx_{2}+tanx_{3}}{1-tanx_{2}tanx_{3}-tanx_{1}tanx_{2}-tanx_{1}tanx_{3}}$

$=\frac{tanx_{1}+tanx_{2}+tanx_{3}-tanx_{1}tanx_{2}tanx_{3}}{1-tanx_{1}tanx_{2}-tanx_{2}tanx_{3}-tanx_{1}tanx_{3}}$

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3 years ago

AlexFokin [52]

The answer in 14.3

You use a proportion to compare AE with AD and AB with AC.

9/14 = 9.2/x
x=14.3
(14 is the length of AD)

8 0

3 years ago