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4 years ago

Change each improper fraction into an equal mixed number.

Mathematics

1 answer:

zalisa [80]4 years ago

6 0

15/4 = 3 3/4

41/9 = 4 5/9

67/8 = 8 3/8

135/11 = 12 3/11

107/20 = 5 7/20

493/174 = 2 145/174

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If the original price is 82$ and the sale price is 65.60 then what is the percent of discount

Liula [17]

82(1 - x) = 65.60

82 - 82x = 65.60

82x = 16.4

x = 0.2

The percent of discount is 20%

5 0

3 years ago

Please hurry!!!

Finger [1]

side of the triangle = 12 inches

side of the square = 8 inches

12 is 4 more than 8

perimeter of the square = 4(8) =32 inches

perimeter of the triangle = 3(12) = 36 inches

36 is 4 more than 32

Let T= side of the triangle and S = side of the square

3T = 4S+4

T=S+4

3(S+4) = 4S+4

3S+12 = 4S +4

4S-3S = S = 12-4 = 8

T =8+4 = 12

8 0

3 years ago

A classroom board is 54 inches wide and 36 inches tall. Eva

Lady bird [3.3K]

<h3>Answer: 180 inches</h3>

Work Shown:

L = 54 = length

W = 36 = width

P = 2(L+W) ... perimeter of the rectangle

P = 2(54+36)

P = 2(90)

P = 180

She needs 180 inches of ribbon.

To convert to feet, divide by 12. So 180 inches = 180/12 = 15 feet.

8 0

2 years ago

In the expression 4x3 + 12, which is a coefficient, which is the variable, and which is a constant?

Salsk061 [2.6K]

Answer:

4 and 3 are coefficanta and 12 will be a constant.

if 4 and 3 are being shared by the variable they would be coefficants

if x is not a variable then all the numbers are constants

Step-by-step explanation:

5 0

3 years ago

Someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi. We think the

denpristay [2]

Answer:

The sample size must be greater than 37 if we want to reject the null hypothesis.

Step-by-step explanation:

We are given that someone claims that the breaking strength of their climbing rope is 2,000 psi, with a standard deviation of 10 psi.

Also, we are given a level of significance of 5%.

Let $\mu$ = <u><em>mean breaking strength of their climbing rope</em></u>

SO, Null Hypothesis, $H_0$ : $\mu$ = 2,000 psi {means that the mean breaking strength of their climbing rope is 2,000 psi}

Alternate Hypothesis, $H_A$ : $\mu$ < 2,000 psi {means that the mean breaking strength of their climbing rope is lower than 2,000 psi}

Now, the test statistics that we will use here is One-sample z-test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = ample mean strength = 1,997.2956 psi

$\sigma$ = population standard devaition = 10 psi

n = sample size

Now, at the 5% level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

So, to reject our null hypothesis our test statistics must be less than -1.645 as only then we have sufficient evidence to reject our null hypothesis.

SO, T.S. < -1.645 {then reject null hypothesis}

$\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < -1.645$

$\frac{1,997.2956-2,000}{\frac{10}{\sqrt{n} } } < -1.645$

$(\frac{1,997.2956-2,000}{10}) \times {\sqrt{n} } } < -1.645$

$-0.27044 \times \sqrt{n}< -1.645$

$\sqrt{n}> \frac{-1.645}{-0.27044}$

$\sqrt{n}>6.083$

n > 36.99 ≈ 37.

SO, the sample size must be greater than 37 if we want to reject the null hypothesis.

7 0

4 years ago