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Ilia_Sergeevich [38]
4 years ago
11

Consider the diagram. What is the length of segment AB? A) 7 B) 9 C) 18 D) 25

Mathematics
1 answer:
AnnyKZ [126]4 years ago
7 0

Answer:

the answer is 9

Step-by-step explanation:

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PLEASE HELP ME I WILL MARK BRAINLYEST
Korvikt [17]

                               Question 9:

Given the equations

5x+2y=6;

4x-8y=0

solving the system of the equations

\begin{bmatrix}5x+2y=6\\ 4x-8y=0\end{bmatrix}

\mathrm{Multiply\:}5x+2y=6\mathrm{\:by\:}4\:\mathrm{:}\:\quad \:20x+8y=24

\mathrm{Multiply\:}4x-8y=0\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:20x-40y=0

\begin{bmatrix}20x+8y=24\\ 20x-40y=0\end{bmatrix}

20x-40y=0

-

\underline{20x+8y=24}

-48y=-24

\begin{bmatrix}20x+8y=24\\ -48y=-24\end{bmatrix}

-48y=-24

\frac{-48y}{-48}=\frac{-24}{-48}

y=\frac{1}{2}

y = 0.5 ( 0.5 is the result of rounding 0.5 to the nearest 0.01)

\mathrm{For\:}20x+8y=24\mathrm{\:plug\:in\:}y=\frac{1}{2}

20x+8\cdot \frac{1}{2}=24

20x+4=24

\frac{20x}{20}=\frac{20}{20}

x=1.00 ( 1.00 is the result of rounding 1 to the nearest 0.01 )

So, the solution is:

(x, y) → (1.00, 0.5)

                            Question 10)

Similarly the question 10 can be solved.

Given the equations

5x+2y=9;\:4x-3y=44

solving

\begin{bmatrix}5x+2y=9\\ 4x-3y=44\end{bmatrix}

\mathrm{Multiply\:}5x+2y=9\mathrm{\:by\:}4\:\mathrm{:}\:\quad \:20x+8y=36

\mathrm{Multiply\:}4x-3y=44\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:20x-15y=220

\begin{bmatrix}20x+8y=36\\ 20x-15y=220\end{bmatrix}

20x-15y=220

-

\underline{20x+8y=36}

-23y=184

\begin{bmatrix}20x+8y=36\\ -23y=184\end{bmatrix}

-23y=184

y=-8.00   ( -8.00 Rounded to the nearest 0.01 or  the Hundredths Place )

\mathrm{For\:}20x+8y=36\mathrm{\:plug\:in\:}y=-8

20x+8\left(-8\right)=36

20x=100

x=5.00  ( 5.00 Rounded to the nearest 0.01 or  the Hundredths Place )

So, the solution is:

(x, y) → (5.00, -8.00)

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Step-by-step explanation:

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My reactions to this:

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Please help me with #16 I am really bad at doing fractions
emmasim [6.3K]
To see if it's a right triangle we need to determine if a²+b²=c²
(\frac{3}{20})² + (\frac{1}{5})² = \frac{1}{4}
\frac{9}{400} + \frac{1}{25} = \frac{1}{16}
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So it is a right triangle
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