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Ilia_Sergeevich [38]
3 years ago
11

Consider the diagram. What is the length of segment AB? A) 7 B) 9 C) 18 D) 25

Mathematics
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

the answer is 9

Step-by-step explanation:

You might be interested in
3 3/4 divided by 3/4
scZoUnD [109]

Answer:

5

Step-by-step explanation:

3 3/4 divided  by 3/4  is equal to 15/4 divided by 3/4

which is 15/4 times 4/3  the 4's cancel each other out making it 15/3 which is 5

3 0
3 years ago
Read 2 more answers
Find the value of x - please help!
aleksklad [387]

Answer:

x=32

Step-by-step explanation:

you have to solve by taking the interior angle of polygon

6 0
3 years ago
F = (4x-3)au carre - (x+3)(3-9x)
Vinvika [58]

Answer:

<em>Translater</em>

Step-by-step explanation:

<em>F = (4x-3) squared - (x + 3) (3-9x)</em>

<em>- develop and reduce (4x-3) to the edge</em>

<em>- show that F = (5x) squared</em>

<em />

  • <em>(NOT AN ANSWER ITS TO HELP OTHERS WHO DOESN"T KNOW FRENCH)</em>
7 0
3 years ago
The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in
Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
3 years ago
What is the next number in the pattern: 3, 6, 7, 14, 15, 30, 31, 62, 63, …
Leviafan [203]
The pattern goes like this:
one number, the next number is the first number doubled, then the third number is the second number + 1, and so on.
So, you see that 3 * 2 = 6, and then 6 + 1 = 7, and so on. This means that you have to multiply 63 by 2, and get 126, and then add 1 to get 127.
So, the next number in the pattern is 126. 
3 0
3 years ago
Read 2 more answers
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