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3 years ago

NO LINKS OR ELSE YOU'LL BE REPORTED!Only answer if you're very good at Math.

Mathematics

1 answer:

andreev551 [17]3 years ago

4 0

Answer:

$D.\ y = 3\sin(2(x + \frac{\pi}{4}))$

Step-by-step explanation:

Given

$A = 3$ --- Amplitude

$C = \frac{\pi}{4}$ --- Right phase shift

Required

Identify the function

A sinusoidal function is defined as:

$y = A\sin(B(x + C)) + D$

Substitute values for A and C

$y = 3\sin(B(x + \frac{\pi}{4})) + D$

By comparison, only option (D) has the above format where

$y = 3\sin(2(x + \frac{\pi}{4}))$

Hence (D) is correct

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5. m∠C = 95°

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11. m∠B = 70°

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A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:

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5. m∠C = 180 - 50 - 35 [triangle sum theorem]

m∠C = 95°

6. m∠C = 180 - 25 - 85 [triangle sum theorem]

m∠C = 70°

7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]

The other acute angle = 70°

8. m∠C = 180 - 55 - 55 [isosceles triangle]

m∠C = 70°

9. m∠C = 60° [equilateral triangle]

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2 years ago

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2 years ago

What is the answer to 132.55=5 (0.04m+21.70+0.10(21.70))

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132.55=5(.04m+2+.7+0.1(21.7))>>>m=66

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3 years ago

Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

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3 years ago