She could write 18 is a multiple of 9 but im nt sure if that answer is correct
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
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b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
8 in
I have that is the correct answer
but iam not confident
Answer:
12 inches
Step-by-step explanation:
The formula for a trapezoid is
A = 1/2(a +b)h
The formula to find the height =
h = 2A/a + b
A= 216 in²
a =14 in
b = 22 in
Hence,
h = 2 × 216/14 + 22
h = 12 inches
The height of the trapezoid = 12 inches