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ivanzaharov [21]
3 years ago
14

What is the area of this polygon?

Mathematics
2 answers:
ra1l [238]3 years ago
6 0
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)

Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9. 

Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27

Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45

Final Answer: 45 square units

note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
Dmitrij [34]3 years ago
5 0

Answer:

45

Step-by-step explanation:

i just took the test

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ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

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(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

We now put y=5 into the expansion to get,

(x - 5) ^{5}  =  {x}^{5}  - 5 {x}^{4} (5) + 10 {x}^{3} ( {5}^{2})  - 10 {x}^{2}  ({5})^{3}  + 5x( {5})^{4}  - {5}^{5}

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

3 0
3 years ago
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