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GrogVix [38]
3 years ago
15

0=(1x+1)(1x-3) if m(x) =10, find the value of x

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

x=1+sqrt(14) & 1-sqrt(14).

Step-by-step explanation:

(1x+1)(1x-3)=0

(x+1)(x-3)=0

m(x)=(x+1)(x-3)=10

(x+1)(x-3)=10

x^2+x-3x-3=10

x^2-2x-3=10

x^2-2x-3-10=0

x^2-2x-13=0

Apply the quadratic formula with a=1, b=-2 and c=-13.

The answer is x=1+sqrt(14) & 1-sqrt(14).

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What is the value of 0.8–0.6? Write your answer as a fraction in lowest terms
Nesterboy [21]

Given expression:

  • 0.8 - 0.6

To simplify the expression as a fraction in simplest form, let us multiply both terms by 10. Then, both terms must also be divided by 10.

   \implies \dfrac{[10(0.8) - 10(0.6)]}{10}

   \implies \dfrac{[8 - 6]}{10}

   \implies \dfrac{[2]}{10} = \dfrac{2}{10}

When 2/10 is simplified in lowest terms, we get;

   \implies \dfrac{2}{10} \implies \dfrac{1 \times 2}{5 \times 2} \implies \dfrac{1}{5}

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4 0
2 years ago
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Answer:

40

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7(4)+2(4)+(4)=?

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3 years ago
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4 0
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Numerator ( N)
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149/100
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