So the problem is, what is the least number than can be divided into 6, 7 and 8? The numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3. So for our drives we can "delete" one 2 and ask: what is the smallest number than can be divided into 3,7 and 8 ? There are no more divisors in common, so we just have to multiply them: 3*7*8 = 21*8=168 and the 4 marbles "extra"? We add them to this sum. So, the smallest possible number in the box is 168 + 4 = 172.
Answer:
4
Step-by-step explanation:
74
82-8=74
Up is the y value and left is the x value.
In the point ( t,u) t is the x value and u is the y value.
Moving to the left, you subtract the value and moving up you add the value.
The answer would be (t, u) → (-t – 3, u + 8)
