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3 years ago

5

The following phrase is an algebraic expression. Use Z for the unknown.

1 answer:

ioda3 years ago

8 0

Answer:

$\frac{14}{z\\}$

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Help! Please? The ratio (by volume) of milk in a certain solution is 3 to 8. If the total volume of the solution is 187 cubic fe

DIA [1.3K]

We know that the total volume of the solution is 187 cubic feet.
187=3x+8x
187=11x
17=x
Now we know that the ratio 3 to 8 is 51 to 136.
Double check, (3*17)+(8*17)=187.
I'm not sure which part of the ratio is water, but knowing this information, you should be able to solve it. I believe it may be this:
The total volume of milk is 51. If the rest of the solution is water, then 187-51=136.

6 0

3 years ago

Find the surface area

Helen [10]

We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area. Hope this helps!

3 0

3 years ago

Read 2 more answers

2. Kyle owes his sister 24. He gives his sister $15 that he earned mowing

rusak2 [61]

ok so he is owing his sister 24 and he gives her 15

so 24-15=9

but as an addition expression it will be

x+15=24

x=24-15

x=9

3 0

2 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

2 years ago

Can you please help? The question is in the picture picture. thank you

Naddika [18.5K]

Given:

The value is $\dfrac{\sqrt{2}}{2}$ .

To find:

The values from the given options which are equal to the given value.

Solution:

We have,

$\dfrac{\sqrt{2}}{2}$

It can be written as:

$\dfrac{\sqrt{2}}{2}=\dfrac{1}{\sqrt{2}}$

From the standard trigonometric table, we get

$\sin 30^\circ=\dfrac{1}{2}$

$\sin 45^\circ=\dfrac{1}{\sqrt{2}}$

$\cos 45^\circ=\dfrac{1}{\sqrt{2}}$

$\cos 60^\circ=\dfrac{1}{2}$

$\tan 30^\circ=\dfrac{1}{\sqrt{3}}$

$\tan 45^\circ=1$

From the above values it is clear that the value of $\sin 45^\circ$ and $\cos 45^\circ$ are equal to $\dfrac{1}{\sqrt{2}}$ .

Therefore, $\sin 45^\circ$ and $\cos 45^\circ$ and equal to $\dfrac{\sqrt{2}}{2}$ . So, options B and C are correct.

4 0

2 years ago