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Annette [7]
3 years ago
9

F(x)=9x^2 g(x)= sqrt 12-x/3 (f o g)(-4)

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0

f(x)=9x^2 \\ g(x)=\frac{\sqrt{12-x}}{3} \\ So,first step is to write (fog)(-4)) =f[g(-4)] \\

Now we start from inner paranthesis ,we need to first find value of g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\
=\frac{\sqrt{16}}{3}\\
=\frac{4}{3}\\
(fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16     

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