We can write this as
(x - 5)^2 + (y + 3)^2 = r^2
where r = radius
Plugging in the point (2,5) we have
(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is
(x - 5)^2 + (y + 3)^2 = 73
1 x 10 = 10
16 x 1 = 16
10 + 16 =
26
Answer:
(4, 1)
Step-by-step explanation:
For any rectangle or square located on the axes, match the pairs and find what's missing. 3 -- 3, 4 -- 4. unmatched are 4 and 1. 4 is x because it's missing from x and same for 1 and y.
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Answer: 15 students
Step-by-step explanation:
From the question, we are informed that there are 150 students in 6th grade, and that 10% earned straight As last quarter.
The number of students that earned straight As will be:
= 10% × 150
= 10/100 × 150
= 0.1 × 150
= 15 students
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)