Let x be a variable, and f(x) a function of that variable.
f(2) is a <em>number </em>; it's the value of the function f(x) when x = 2, assuming that value exists.
f(x) = 2 is a <em>statement </em>; it says there is some value of x for which the function returns a value of 2. Because it's a statement, it can be true or false.
Here's an example:
Define f(x) = sin(x). Then f(2) = sin(2) ≈ 0.909297.
If x is a real number, then the statement sin(x) = 2 is false, because -1 ≤ sin(x) ≤ 1 for all real x.
If we replace 2 with 1, on the other hand, we get
f(1) = sin(1) ≈ 0.84147
and
sin(x) = 1 ==> x = π/2 + 2nπ
where n is any integer. (So we're talking about numbers like π/2, -3π/2, 5π/2, -7π/2, and so on.) We're saying here that any real number x of the above form satisfies the equation and makes the statement true.
Answer:
if that arrow stands for an equal, than x=28
Answer:
1/3 +1/3+1/3
Step-by-step explanation:
Add all three to get a whole.
Answer:
F(2)=8 and G(2)=4
Step-by-step explanation:
Step by Step Solution
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System of Linear Equations entered :
[1] -4x - 3y = -7
[2] 16x - 3y = 13
Graphic Representation of the Equations :
-3y - 4x = -7 -3y + 16x = 13
Solve by Substitution :
// Solve equation [2] for the variable x
[2] 16x = 3y + 13
[2] x = 3y/16 + 13/16
// Plug this in for variable x in equation [1]
[1] -4•(3y/16+13/16) - 3y = -7
[1] - 15y/4 = -15/4
[1] - 15y = -15
// Solve equation [1] for the variable y
[1] 15y = 15
[1] y = 1
// By now we know this much :
x = 3y/16+13/16
y = 1
// Use the y value to solve for x
x = (3/16)(1)+13/16 = 1
Solution :
{x,y} = {1,1}
