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jek_recluse [69]
4 years ago
10

What is the x-intercept and the Y-intercept? Y=-2/3x

Mathematics
2 answers:
Mandarinka [93]4 years ago
8 0

Answer:

Y-intercept is 0 and x intercept is also 0

Step-by-step explanation:

qaws [65]4 years ago
5 0

Both the x-intercept and y-intercepts are 0.

The x and y-intercepts are zero because the graph does not cross the x or y-axis. Instead, this function passes through the origin. The slope of this function is -2/3.

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4 terms, degree of 2

The terms is the amount of “numbers” you have, which is 4
The degree is the highest power, which is x^2
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Because the shaded section is "below" the line, you know that it's less than or equal to something. Next, observe that the y-intercept (where the line crosses the y-axis and x=0) is at positive 4. This means that the correct answer is D: y <(or equal to) -3x+4
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VashaNatasha [74]

The total number of coins required to fill all the 64 boxes are \boxed{\bf 18446744073709551615}.

Further explanation:

In a chessboard there are 64 boxes.

The objective is to determine the total number of coins required to fill the 64 boxes in chessboard.

In the question it is given that in the first box there is 1 coin, in the second box there are 2 coins, in the third box there are 8 coins and it continues so on.

A sequence is formed for the number of coins in different boxes.

The sequence formed for the number of coins in different boxes is as follows:

\boxed{1,2,4,8,...}

The above sequence can also be represented as shown below,

\boxed{2^{0},2^{1},2^{2},2^{3},...}

It is observed that the above sequence is a geometric sequence.

A geometric sequence is a sequence in which the common ratio between each successive term and the previous term are equal.

The common ratio (r) for the sequence is calculated as follows:

\begin{aligned}r&=\dfrac{2^{1}}{2^{0}}\\&=2\end{aligned}

The n^{th} term of a geometric sequence is expressed as follows:

\boxed{a_{n}=ar^{n-1}}

In the above equation a is the first term of the sequence and r is the common ratio.

The value of a and r is as follows:

\boxed{\begin{aligned}a&=1\\r&=2\end{aligned}}

Since, the total number of boxes are 64 so, the total number of terms in the sequence is 64.

To obtain the number of coins which are required to fill the 64 boxes we need to find the sum of sequence formed as above.

The sum of n terms of a geometric sequence is calculated as follows:

\boxed{S_{n}=a\left(\dfrac{r^{n}-1}{r-1}\right)}

To obtain the sum of the sequence substitute 64 for n, 1 for a and 2 for r in the above equation.

\begin{aligned}S_{n}&=1\left(\dfrac{2^{64}-1}{2-1}\right)\\&=\dfrac{18446744073709551616-1}{1}\\&=18446744073709551615\end{aligned}

Therefore, the total number of coins required to fill all the 64 boxes are \boxed{\bf 18446744073709551615}.

Learn more:

1. A problem on greatest integer function brainly.com/question/8243712  

2. A problem to find radius and center of circle brainly.com/question/9510228  

3. A problem to determine intercepts of a line brainly.com/question/1332667  

Answer details:  

Grade: High school  

Subject: Mathematics  

Chapter: Sequence

Keywords: Series, sequence, logic, groups, next term, successive term, mathematics, critical thinking, numbers, addition, subtraction, pattern, rule., geometric sequence, common ratio, nth term.

3 0
3 years ago
Please help and hurry 25 points
evablogger [386]

Answer:

1. Motet

2. Conductus

3. Organum

4. Gregorian Chant

Step-by-step explanation:

4 0
2 years ago
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