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2 years ago

Please help I'll give brainliest! And 100 points this is due tonight!!!

Mathematics

1 answer:

AlladinOne [14]2 years ago

8 0

Answer:

You can try searching it up or going to math.way

Step-by-step explanation:

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The math team does practice drills that each last 1/6 hour. In February the team did practice drills for a total of 24 hours. Ho

kozerog [31]

144 classes. each class is 10 minutes. 6X24= 144

7 0

3 years ago

Factor. Explain. 24x³y²-4x²y+84x^4

Elan Coil [88]

Answer:

$\boxed{\bold{4x^2\left(6xy^2-y+21x^2\right)}}$

Step By Step Explanation:

Apply Exponent Rule $\bold{\:a^{b+c}=a^ba^c}$

$\bold{x^4=x^2x^2,\:x^3y^2=x^2x}$

$\bold{24x^2x-4x^2y+84x^2x^2}$

Rewrite 84: $\bold{21\cdot \:4}$

Rewrite 24: $\bold{6\cdot \:4}$

$\bold{6\cdot \:4x^2x-4x^2y+21\cdot \:4x^2x^2}$

Factor Out Common Term $\bold{4x^2}$

$\bold{4x^2\left(6xy^2-y+21x^2\right)}$

➤ $\boxed{\bold{Mordancy}}$

6 0

2 years ago

Mr. Mole left his burrow and started digging his way down at a constant rate.

Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute $= \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},$

$\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.$

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow $= -18 - 5(-2.4) = -18+12 = -6.$

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

5 0

3 years ago

Read 2 more answers

Marat540 [252]

Answer:

Plan A equation: y = 10x + 30

Plan B equation: y = x + 80

Plan C equation: y = 5x + 50

Plan A costs the same as Plan C in 4 months

Plan A is the better option if you use 0 - 4 GBs of data each month

Plan B becomes the better deal when 8 months pass

Step-by-step explanation:

When does Plan A cost the same as Plan C?

Set the equations equal to each other (the cost) and solve for x (time in months)

10x + 30 = 5x + 50

5x = 20

x = 4 months

Which plan is best if you only use 0-4 GBs of data a month?

Test the maximum and minimum values to check which plan costs less

At 0 GBs of data used per month

Plan A: y = 0 + $ 30 = $30 total

Plan B: y = 0 +$80 = $80 total

Plan C: y = 0 + $50 = $50 total

At 4 GBs of data used per month

Plan A: y = $ 40 + $ 30 = $ 70

Plan B: y = $ 4 + $ 80 = $ 84

Plan C: y = $ 20 + $ 50 = $ 70

Comparing the plans at maximum and minimum amount of GBs used, only one plan has the lowest cost overall. Even though Plan C is the same price at 4 GBs as Plan A, when you use 0 GBs you will end up paying more in Plan C than Plan A. Therefore, Plan A is the better option

When does Plan B become the best deal?

When you plot the different Plans on a graph, the slope intercept of x = 7.5 (rounded up to 8) yields the lowest cost for plan B

5 0

2 years ago

What is the quotient of 6,135 and 15

zavuch27 [327]

Answer:

409

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers