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morpeh [17]
2 years ago
9

Please help I'll give brainliest! And 100 points this is due tonight!!!

Mathematics
1 answer:
AlladinOne [14]2 years ago
8 0

Answer:

You can try searching it up or going to math.way

Step-by-step explanation:

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The math team does practice drills that each last 1/6 hour. In February the team did practice drills for a total of 24 hours. Ho
kozerog [31]

144 classes. each class is 10 minutes. 6X24= 144

7 0
3 years ago
Factor. Explain.<br> 24x³y²-4x²y+84x^4
Elan Coil [88]

Answer:

\boxed{\bold{4x^2\left(6xy^2-y+21x^2\right)}}

Step By Step Explanation:

Apply Exponent Rule \bold{\:a^{b+c}=a^ba^c}

\bold{x^4=x^2x^2,\:x^3y^2=x^2x}

\bold{24x^2x-4x^2y+84x^2x^2}

Rewrite 84: \bold{21\cdot \:4}

Rewrite 24: \bold{6\cdot \:4}

\bold{6\cdot \:4x^2x-4x^2y+21\cdot \:4x^2x^2}

Factor Out Common Term \bold{4x^2}

\bold{4x^2\left(6xy^2-y+21x^2\right)}

➤ \boxed{\bold{Mordancy}}

6 0
2 years ago
Mr. Mole left his burrow and started digging his way down at a constant rate.
Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute = \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},

\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow = -18 - 5(-2.4) = -18+12 = -6.

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

5 0
3 years ago
Read 2 more answers
7
Marat540 [252]

Answer:

Plan A equation:   y = 10x + 30

Plan B equation:  y = x + 80

Plan C equation: y = 5x + 50

Plan A costs the same as Plan C in 4 months

Plan A is the better option if you use 0 - 4 GBs of data each month

Plan B becomes the better deal when 8 months pass

Step-by-step explanation:

<u>When does Plan A cost the same as Plan C?</u>

Set the equations equal to each other (the cost) and solve for x (time in months)

10x + 30 = 5x + 50

5x = 20

x = 4 months

<u>Which plan is best if you only use 0-4 GBs of data a month?</u>

Test the maximum and minimum values to check which plan costs less

At 0 GBs of data used per month

Plan A:  y = 0 + $ 30 = $30 total

Plan B: y = 0 +$80 = $80 total

Plan C: y = 0 + $50 = $50 total

At 4 GBs of data used per month

Plan A: y = $ 40 + $ 30 = $ 70

Plan B: y = $ 4 + $ 80 = $ 84

Plan C: y = $ 20 + $ 50 = $ 70

Comparing the plans at maximum and minimum amount of GBs used, only one plan has the lowest cost overall. Even though Plan C is the same price at 4 GBs as Plan A, when you use 0 GBs you will end up paying more in Plan C than Plan A. Therefore, Plan A is the better option

<u>When does Plan B become the best deal?</u>

When you plot the different Plans on a graph, the slope intercept of x = 7.5 (rounded up to 8) yields the lowest cost for plan B

5 0
2 years ago
What is the quotient of 6,135 and 15
zavuch27 [327]

Answer:

409

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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