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schepotkina [342]
3 years ago
15

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Complete the following proof.

Prove: The segment joining the midpoints of two sides of a triangle is parallel to the third side.

Mathematics
1 answer:
azamat3 years ago
4 0
For M:
 (((0+c)/2), ((0+d)/2))=((c/2), (d/2))
 For N:
 (((a+c)/2), ((0+d)/2))=(((a+c)/2), (d/2))
 Slope of MN:
 MN=(y2 - y1)/(x2- x1)
 MN=((d/2) - (d/2))/(((a+c)/2)- (c/2))
 MN=(0/(((a+c)/2)- (c/2))
 MN=0
 Slope of AB:
 AB=(0 - 0)/(a)
 AB=(0)/(a)
 AB=0
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Find AB please help me!!
VladimirAG [237]

Answer:

<em>15</em>

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I need help understanding this ASAP plz, I have a quiz over this next week!!!!
scZoUnD [109]

Answer:

Step-by-step explanation:

With any two points, you can find the line between them with:

y = mx + b\\where\\m = \frac{y_2-y_1}{x_2-x_1}

#1:

(-1, 1) -> (1, 3) m = \frac{3-1}{1-(-1)} = 1, 3 = 1(1) + b, b = 2, y = x + 2

(3, 4) -> (0, 2) m = \frac{4-2}{3-0} = \frac{2}{3}, 2 = \frac{2}{3}(0) + b, y = \frac{2}{3}(x)+2

(0, 1) -> (3, 3) m = \frac{3-1}{3-0} = \frac{2}{3}, 1 = 2/3(0) + b, y = \frac{2}{3}(x) + 1

Lines b and c are parallel because they have the same slopes

#2 is a bit easier

a: 2y = x + 12, y = \frac{1}{2}(x) + 6

b:2y - x = 5, y = \frac{1}{2}(x) + \frac{5}{2}

c: 2y + x = 4, y = \frac{-1}{2}(x) + 2

Since lines a and b have the same slope, they are parallel

#3:

(1, 3), y = 2x - 5

We have to find a line with a slope of 2 that passes through the two points

y = 2x + b\\3 = 2(1) + b\\b = 1\\\\y = 2x + 1

#4:

(-2, 1) , y = -4x + 3

We have to find a line with a slope of-4 that passes through the line

y = -4x + b\\1 = -4(-2) + b\\1 = 8+ b\\b = -7\\y = -4x - 7

#5:

(-2, 3) (1, -1), m = \frac{3-(-1)}{-2-1} = \frac{-4}{3}, 3 = \frac{8}{3} + b, b = \frac{1}{3}, y = \frac{-4x}{3} + \frac{1}{3}

(-3, 1) (1, 4), m = \frac{4-1}{1-(-3)} =\frac{3}{4}, 4 = \frac{3(1)}{4} + b, y = \frac{3}{4}(x) + \frac{13}{4}

(0, 2) (3, -2) m = \frac{2-(-2)}{0-3} = \frac{-4}{3} , 2 = b, y = \frac{-4}{3}(x) + 2

Since lines c and b have negative reciprocal slopes, they are perpendicular

#6:

a: y = -4x + 7

b: x = 4y + 2, y = \frac{x}{4} - \frac{1}{2}

c: -4y + x = 3, y = \frac{x}{4} - \frac{3}{4}

since lines a and c have negative reciprocal slopes, they are perpendicular

6 0
3 years ago
Find the GCF of 260,80,50
pantera1 [17]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
Order from least to greatest.<br> 1/3 ,5/4, 0.85
Sav [38]

Answer:

I believe it should be; 1/3, 0.85, 5/4

4 0
4 years ago
Read 2 more answers
I need help please and thank you
BartSMP [9]

Answer:

  3.33×10⁴

Step-by-step explanation:

You can use the hint, or you can use a common exponent. Here is the latter case.

  (3.9×10⁴) -(5.7×10³) = (3.9×10⁴) -(0.57×10⁴) = (3.9 -0.57)×10⁴

  = 3.33×10⁴

_____

With a little practice, you can see the effect on exponents of moving the decimal point. Here, we have ...

  5.7×10³ = (0.57×10)×10³ = 0.57×(10×10³) = 0.57×10⁴

__

When adding or subtracting in scientific notation, all that is required is that the exponents of all the numbers be the same. The hint says make all the exponents be 0. Above, we have chosen to make them all be 4. You could also use 3:

  (3.9×10⁴) -(5.7×10³) = (39×10³) -(5.7×10³) = (39 -5.7)×10³

  = 33.3×10³ = 3.33×10⁴

6 0
3 years ago
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