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schepotkina [342]
3 years ago
15

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Complete the following proof.

Prove: The segment joining the midpoints of two sides of a triangle is parallel to the third side.

Mathematics
1 answer:
azamat3 years ago
4 0
For M:
 (((0+c)/2), ((0+d)/2))=((c/2), (d/2))
 For N:
 (((a+c)/2), ((0+d)/2))=(((a+c)/2), (d/2))
 Slope of MN:
 MN=(y2 - y1)/(x2- x1)
 MN=((d/2) - (d/2))/(((a+c)/2)- (c/2))
 MN=(0/(((a+c)/2)- (c/2))
 MN=0
 Slope of AB:
 AB=(0 - 0)/(a)
 AB=(0)/(a)
 AB=0
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Although, in general, you cannot know the sampling distribution of the sample mean exactly, by what distribution can you often a
Vitek1552 [10]

Answer:

b: Normal Distribution

Step-by-step explanation:

4 0
3 years ago
URGENT O_O<br><br> Find the roots of the polynomial equation!<br><br> 2x^3+2x^2-19x+20=0
ohaa [14]

The function is

  • y=2x^3+2x^2-19x+20

Graph attached

There is one real zero only

That's-1.047

4 0
2 years ago
The table shows the amount of applesauce made from one apple from each size Patrice has 17 medium apples and 23 large apples was
alexgriva [62]

Hope I helped! Have a wonderful day!

5 0
2 years ago
 Can you solve 2^x=e^(x+2)
mina [271]
<u>Answer:</u> Yes, I can.


Although you haven't asked for the solution, here it is anyway:

2^x = e^(x+2)

x ln(2) = x+2

x ln(2) - x = 2

x [ ln(2) - 1 ] = 2

x = 2 / [ ln(2) - 1 ]

x = 2 / -0.3069... =<u> - 6.518</u>... (rounded) 

8 0
3 years ago
Read 2 more answers
Find an explicit formula for the geometric sequence −1,−7,−49,−343,...-1\,,-7\,,-49\,,-343,... −1,−7,−49,−343
umka21 [38]
So we see it times 7 each time
starting with -1

geometric
an=a1(r)^(n-1)
a1=first term
r=common ratio
first term is -1
r=7

a_n=-1(7)^{n-1} is the formula
also can look like this:
f(n)=-1(7)^{n-1}
7 0
3 years ago
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