<em>Hi there!</em>
<em>This should be easy,lol!</em>
<em>Answer:</em>
<em /><em> (Decimal: -221.702503)</em>
<em /><em> (Decimal: 280.592231)</em>
<em /><em />
<em>Sorry bout the explanation thingy. Their really long -.-!</em>
<em>But the last one is short so i'll put it for you!</em>
<em>Step-by-step explanation:</em>
<em>∴!For the last one!∴</em>
<em /><em />
<em>Simplifies to:</em>
<em /><em />
<em /><em> </em>
<em /><em />
<em>Have a great day/night!</em>
Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>
Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
There is an 84.97% probability that at least six wear glasses.
Step-by-step explanation:
For each adult over 50, there are only two possible outcomes. Either they wear glasses, or they do not. This means that we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem we have that:
What is the probability that at least six wear glasses?
There is an 84.97% probability that at least six wear glasses.