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shepuryov [24]
3 years ago
11

90,95,101,98,103,119,124,123,132,127 what is the mean

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

Step-by-step explanation:

Add all the numbers to get 1004

then divide by 10 since there are 10 numbers

So 100.4

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0.4 times 0.59<br> sgaehags
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0.236

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The Arc Electronic Company had an income of 59 million dollars last year. Suppose the mean income of firms in the same industry
Zolol [24]

Answer:

0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Suppose the mean income of firms in the same industry as Arc for a year is 45 million dollars with a standard deviation of 7 million dollars

This means that \mu = 45, \sigma = 7

What is the probability that a randomly selected firm will earn more than Arc did last year?

Arc earned 59 million, so this is 1 subtracted by the pvalue of Z when X = 59.

Z = \frac{X - \mu}{\sigma}

Z = \frac{59 - 45}{7}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year

7 0
2 years ago
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