Ask question

Ask question

All categories

3 years ago

14

Please help with the image!! Use the Exterior Angle Theorem to find the measure of each angle. 83 points!!!!!!

2 answers:

Andrej [43]3 years ago

8 0

Answer:

Step-by-step explanation:

solve E 1st as its the easiest -

<E + 113deg = 180deg

<E = 180 - 113 = 67deg

by exterior angle theorem, <C + <D = 113deg

so 3y+5 + 7y+8 = 113

10y=100

y=10

<C = 3(10)+5 = 35deg

<D = 7(10)+8 = 78deg

Hunter-Best [27]3 years ago

7 0

Answer:

D = 78

C = 35

DEC = 67

Step-by-step explanation:

Using the theorem, angle D and + angle C = 113 degrees.

Then you can set up the equation 10x + 13 = 113. Then you can find x - it's 10.

Then you plug it back in, and angle D = 78 and angle C = 35

You might be interested in

Dmitry [639]

Factor By Grouping
GCF

7 0

2 years ago

If tan A = 4/5; what does CSC A =?<br> Round to nearest tenth.

ZanzabumX [31]

Answer:

1.6

Step-by-step explanation:

$\tan \: A = \frac{4}{5} \\ \\ \cot \: A = \frac{1}{ \tan \: A } = \frac{1}{ \frac{4}{5} } = \frac{5}{4} \\ \\ csc\: A = \sqrt{1 + {cot}^{2}\: A} \\ = \sqrt{1 + { \bigg( \frac{5}{4} \bigg)}^{2} } \\ = \sqrt{1 + \frac{25}{16} } \\ = \sqrt{\frac{16 + 25}{16} } \\ = \sqrt{\frac{41}{16}} \\ = \frac{ \sqrt{41} }{4} \\ = \frac{6.40312424}{4} \\ = 1.60078106 \\ \therefore \: csc \: A =1.6$

6 0

3 years ago

Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min

leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2}$ .

First, we simplify the expression in the numerator of the fraction.

$3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72$

Now, we obtain

$12(x^2-x-6) = 12(x+2)(x-3)$

and the fraction is transformed into

$\frac{3(2x-1)^2 - 75}{x+2} = \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)$

Therefore, the following limit is

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2} 12(x-3) = 12 \lim_{x \to -2} (x-3)$

You can plug in $-2$ in the equation, hence

$12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60$

6 0

3 years ago

A ball is chosen at random from a bag containing 150 balls that are either red or blue and either dull or shiny. There are 36 re

tino4ka555 [31]

Answer:

The probability of the chosen ball being shiny conditional on it being red is; 0.375

Step-by-step explanation:

Let A be the event that a red ball has been chosen

Let B be the event that a shiny ball has been chosen

Let S be the total outcomes = 150 balls

Thus;

P(A ∩ B ) = 36/150

A ∩ B' = 150 - 36 - 54

A ∩ B' = 60

Thus; P(A ∩ B') = 60/150

P(A') = 54/150

P(A) = (150 - 54)/150 = 96/150

Thus, probability of the chosen ball being shiny conditional on it being red is;

P(B | A) = P(B ∩ A)/P(A)

Thus; P(B | A) = (36/150)/(96/150)

P(B | A) = 0.375

8 0

2 years ago

What’s 20 divided by 20 im tired

MaRussiya [10]

Answer:

The answer to 20 ÷ 20 is 1

7 0

3 years ago

Read 2 more answers