The set of all values for which the function is defined
0.418
x 0.1
-———-
0418
+ 0000
————
0.0418 ✨
Answer:
C
Step-by-step explanation:
5/2x<_-14
5x<_-28
5x/5<_-28/6
X<_-5.6
Answer:
489.84 m²
Step-by-step explanation:
Area of one 2d circle: πr² ⇒ π6² ⇒ 36π ≈ 113.04 (using 3.14 for pi)
Area of both 2d circles: 113.04 + 113.04 =226.08 m²
Now we have to find the width of the rectangle, which is equal to the circumference of either circle:
Width of rectangle: 2πr ⇒ 2π6 = 12π ≈ 37.68 (using 3.14 for pi)
We can find the area of the rectangle now, since the length was given
Area of rectangle: 37.68· 7= 263.76 m²
Surface Area: 263.76+226.08= 489.84m²
Hopefully this helps!
Answer:
To Prove: Quadrilateral ABCD is a parallelogram.
Proof: In Δ ABE and ΔCDE
1. AE = EC and BE = ED [ Diagonals bisect each other]
2.∠ AEB = ∠ CED [ vertically opposite angles]
Δ ABE ≅ ΔCDE---------- [SAS]
∠ ACD ≅ ∠CAB [Corresponding angles of congruent triangles are congruent⇒This statement is untrue ∴ these are alternate interior angles not corresponding angles.]
6. The converse of alternate interior interior angle theorem states that if two parallel lines are cut by a transversal then alternate interior angles are equal.
7. In ΔBEC and ΔAED
∠BEC = ∠AED [ Vertical Angles Theorem ]
AE = EC and BE = ED [ Diagonals bisect each other]
⇒ ΔBEC≅ ΔDEA [ SAS criterion for congruence]
9. DBC ≅ BDA [ Corresponding angles of congruent triangles are congruent⇒This statement is untrue ∴ these are alternate interior angles not corresponding angles.]
As pair of triangles are congruent ∵ quadrilateral ABCD is a parallelogram.
Step 3 is m∠AEB = m∠CED
These pair of angles are vertically opposite angles of ΔAEB and ΔCED.
Option [D. Vertical Angles Theorem] is correct.