Answer:
The given statement is correct for all positive integers.
Step-by-step explanation:
The given inequality is
for all positive integers
Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
It is greater than 5/7. 5/7<1, and sqrt(5)>2
Answer:
This: Im sorry but, I can't type it all, I just looked up some help.
Step-by-step explanation:
You can rewrite the equation as
5
x
−
3
x
+
8
=
−
10
Then
5
x
−
3
x
=
2
x
So
2
x
+
8
=
−
10
Then, to move the whole numbers to one side, you subtract
8
from both sides
2
x
=
−
18
To get rid of the
2
in front of the
x
, divide both sides by
2
x
=
−
9
Y
=
−
2
x
+
5
y
=
-
2
x
+
5
Use the slope-intercept form to find the slope and y-intercept.
Tap for more steps...
Slope:
−
2
-
2
y-intercept:
(
0
,
5
)
(
0
,
5
)
Any line can be graphed using two points. Select two
x
x
values, and plug them into the equation to find the corresponding
y
y
values.
Tap for more steps...
x
y
0
5
5
2
0
