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Ostrovityanka [42]
3 years ago
7

What does 1 - 0.0098 equal?

Mathematics
1 answer:
elena-s [515]3 years ago
5 0
The answer is 0.9902 please give 5 stars if helpful
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The veterinarian weighed Oliva's new puppy, Benz, on a defective scale.
Mrrafil [7]

Answer:

\boxed{x = 10.28 \%}

Step-by-step explanation:

\frac{(26.75)x}{100} = 2.75 \\  \boxed{x = 10.280373832}

5 0
3 years ago
Bradley completed 3/5 of his homework. What percent of his homework does he still need to complete?
muminat
3/5 = 6/10 (which is 60%) 100% - 60% = 40%
7 0
4 years ago
Read 2 more answers
What is the volume of a cylinder with a base radius of 2 and height of 6 ?
vodomira [7]

Answer:

V = 24pi

or 75.36 ( using 3.14 for pi)

or 75.39822369 ( using the pi button)

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

We know the radius and the height

V = pi (2)^2 * 6

V = pi 4*6

V = 24 pi

If we approximate pi by 3.14

V = 3.14 * 24 = 75.36

If we use the pi button

V =75.39822369

8 0
3 years ago
Read 2 more answers
The table shows the relationship between the number of Calories Lucie burns while jumping rope and the number of minutes she jum
iragen [17]

Answer:

The amount of calories Lucie will burn by jumping for 1 minute is 8 calories

Step-by-step explanation:

The given data values are;

Minutes {}                  Calories Burned

40                {}            320

80        {}                    640

120 {}                          960

160 {}                          1280

The value of calories burnt and the number of minutes of jump robe are seen to be directly proportional, such that we have;

40 minutes of jump rope will yield 320 calories burnt

Therefore we have;

1 minute of jump rope will yield 320/40 = 8 calories burnt

The amount of calories Lucie will burn by jumping for 1 minute = 8 calories.

8 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
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