3 years ago

A rectangle has width w and its length is 2 units shorter that 3 times the width

1 answer:

8 0

2(3w-2+w)
=2(4w-2)
=8w-4

the formula for solving perimeters is 2(WL). so L=3w-2, because the question said the length is 2 units shorter than 3 times the width, and the width is w. so the final equation is 2(3w-2+w), and then you just have to simplify that

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