If (4^4)^x = 4^32, what is the value of x?
2 answers:
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Answer:
389 feets apart
Step-by-step explanation:
Given that:
Building A
Height = 400feets
Angle of elevation = 70°
Building B:
Height = 300 feets
Angle of elevation = 52°
Distance from the foot of building A to where Jonny is standing = x (see attached picture)
Using trigonometry :
Tanθ = opposite / Adjacent
Tan 70 = 400/ x
2.7474774x = 400
x = 145.58809 feets
Distance from the foot of building B to where Jonny is standing = y (see attached picture)
Using trigonometry :
Tanθ = opposite / Adjacent
Tan 52 = 300/ y
1.2799416y = 300
y = 145.59
y = 234.38568 feets
x + y = distance between the two buildings
(145.58809 + 234.38568) feets
= 379.97377
= 380 feets apart
