Answer:
A. 0.0746
Step-by-step explanation:
Because it is in the thousandths place
Answer:
3,470,000 pls mark me branilest
The value of the given integral is (3x+2)^2^1 /63 +c
=
=1/3*{(3x-20)^21}/21 +c
=1/63 *(3x-21)^21 +c
=d/dx {1/3*(3x-2)^21}/21 +c
=3/3 *{21(3x-2)}/21 +c
Let u=3x-2
du= 3dx
=
=1/3
=(3x+2)^2^1 /63 +c
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Hello! -56 units is the total charge on 8 particles. To solve this question, all you have to do is divide -56 by 8. Because one number is negative and the other one is positive, the quotient will be negative. -56/8 is -7. There. The charge on each particle is -7 units.
Answer:
20y-14y+4=16
20y+(-14y) -4 -4
6y=12
y=2
Step-by-step explanation:
Combine like terms
subtrate 4 from each side
Divide 6 by 6 and 12 by 6
There for y=2