Reacting with metals is not a common property of bases. Bases do however react with acids.
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
First, let's convert 0.126 g of hydrogen to moles using its molar mass (2.02 g/mol).
Let's consider the steps to make alum (KAl(SO₄)₂⋅12H₂O) from aluminum (Al).
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2 Al(s) + 2 KOH(aq) + 6 H₂O(l) →2 KAl(OH)₄(aq) + 3 H₂(g)
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2 KAl(OH)₄(aq) + H₂SO₄(aq) → 2 Al(OH)₃(s) + K₂SO₄(aq) + 2 H₂O(l)
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2 Al(OH)₃(s) + H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 6 H₂O(l)
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K₂SO₄(aq) + Al₂(SO₄)₃(aq) + 24 H₂O(l) → 2 KAl(SO₄)₂⋅12H₂O(s)
To relate H₂ to KAl(SO₄)₂⋅12H₂O, we need to consider the appropriate molar ratios:
- In step 1, the molar ratio of H₂ to KAl(OH)₄ is 3:2.
- In step 2, the molar ratio of KAl(OH)₄ to Al(OH)₃ is 2:2.
- In step 3, the molar ratio of Al(OH)₃ to Al₂(SO₄)₃ is 2:1.
- In step 4, the molar ratio of Al₂(SO₄)₃ to KAl(SO₄)₂⋅12H₂O is 1:2.
The moles of KAl(SO₄)₂⋅12H₂O produced from 0.0624 moles of H₂ are:
The molar mass of alum is 474.38 g/mol. The mass corresponding to 0.0416 moles is:
Finally, we convert 19.7 grams to pounds using the conversion factor 1 lb = 454 g.
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
You can learn more about molar ratios here: brainly.com/question/15973092
We can change the state of motion of an object by changing its speed, its direction of motion, or both. Acceleration is the rate at which the velocity is changing. In physics, the term acceleration applies to decreases as well as increases in speed.
Answer:
Concentration of the first solution: approximately 0.200 mol/L.
Concentration of the diluted solution: approximately 0.0250 mol/L.
Explanation:
Refer to a modern periodic table for relative atomic mass data:
- H: 1.008;
- S: 32.06;
- O: 15.999.
Formula mass of sulfuric acid :
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Number of moles of in of this substance:
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Convert cubic centimeters to liters:
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Concentration of this solution:
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While both the volume and the concentration of the solution changes when it is diluted, the number of moles of in this solution will stay the same. Number of moles of in this of concentrated solution:
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That will be the same as the number of moles of in the diluted solution.
Concentration of this solution after it is diluted to :
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