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nordsb [41]
3 years ago
11

4. Which of the following is NOT a common property of bases? A. Feels slippery B. tastes bitter C. Reacts with metal D. Changes

colors of indicators
Chemistry
2 answers:
miv72 [106K]3 years ago
4 0

Answer:

C. Reacts with metal

Explanation:

A base is a substance that releases hydroxide ions +OH in water

the following option are true of base:

B. it have a bitter taste e.g milk of magnesia is a base, mustard and soap

A. base have a slippery or soapy feel

D. base changes colour of indicator; red litmus paper is used to test for base. its changes red litmus paper blues in the presence of hydroxide ion.

Option C is not a common properties of base

base are formed when the oxide of some metals dissolve in water.

base react with acid to form salts and water.

alisha [4.7K]3 years ago
3 0

Reacting with metals is not a common property of bases. Bases do however react with acids. 

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Otrada [13]
It’s oxygen we learned about this
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Which of the following reactions is a neutralization reaction? A. ZnCl2(aq) + CaCrO4(aq) → ZnCrO4(s) + CaCl2(aq) B. HNO3(aq) + L
g100num [7]
Neutralization reaction means the reactants must be one acid and one alkali, and the product will be H2O and metal salt.

The only one satisfying this will be B
3 0
3 years ago
Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

#SPJ4

5 0
1 year ago
Calculate the volume of 11 g of CO2 at NTP ?​
Kitty [74]
<h3>Answer:</h3>

5.6 Liters

<h3>Explanation:</h3>
  • N.T.P. refers to the standard temperature and pressure (S.T.P).

We need to know that;

  • One mole of a gas occupies a volume of 22.4 liters at N.T.P.

In this case;

We have 11 g of CO₂

But, 1 mole of CO₂ occupies 22.4 l at N.T.P.

1 mole of CO₂ = 44 g

Therefore;

44 g of CO₂ = 22.4 liters

What about 11 g ?

= (11 g × 22.4 l)÷ 44 g

= 5.6 l

Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.

8 0
3 years ago
A redox reaction can also be a?
AveGali [126]
Losing eltron is the answer
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