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3 years ago

Find the mass of 1.112 moles HF?

Chemistry

1 answer:

Alexeev081 [22]3 years ago

7 0

Answer:

22.25 g

Explanation:

To find the mass, you need to convert moles to grams and get 22.25 g.

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How is biodiversity related to niches?

Alja [10]

Answer:

C. The more niches in an ecosystem, the greater the biodiversity.

Explanation:

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3 years ago

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If the density of an object is 5 g/cm3 and it takes up 7 cm3 of space, calculate the mass?

statuscvo [17]

Answer:

<h2>The answer is option A</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 7 cm³

density = 5 g/cm³

The mass of the object is

mass = 5 × 7

We have the final answer as

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3 years ago

Which of the following compounds will undergo an Sn2 reaction most readily?

Bad White [126]

Answer:

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Explanation:

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2 years ago

H2(g) + O2(9) - H2O(1)

dlinn [17]

Answer:

2H2(g) + O2(g) - 2H2O(l)

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3 years ago

A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific

worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
<u>Thermodynamics</u>

Specific Heat Formula: $\displaystyle q = mc \triangle T$

<em>m</em> is mass (g)
<em>c</em> is specific heat capacity (J/g °C)
Δ<em>T</em> is the change in temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables.</em>

<em>m</em> = 112 g

Δ<em>T</em> = 20.0 °C

<em>q</em> = 1004 J

<u>Step 2: Solve for </u><u><em>c</em></u>

Substitute in variables [Specific Heat Formula]: $\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})$
Simplify: $\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c$
Isolate <em>c</em>: $\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}$
Round [Sig Figs]: $\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}$

∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.

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Topic: AP Chemistry

Unit: Thermodynamics

5 0

2 years ago