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Alinara [238K]
3 years ago
6

How to solve 3(2x-7)=5x+4

Mathematics
2 answers:
otez555 [7]3 years ago
4 0
 The answer to the problem is 
x=25
notka56 [123]3 years ago
3 0
You have to start by using the distributive property on the left side.
3(2x-7)=5x+4
6x-21=5x+4    Then remove and combine alike terms.
    +21      +21
6x=5x+25
-5x  -5x
x=25
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Evaluate the expression.
KATRIN_1 [288]

Step-by-step explanation:

for a³b²c-1d

given

a=2

b=4

c=10

d=15

a³b²c-¹d

=(2³4²10^-1*15

=2³4²15/10

=8*16*15/10

=8*8*3

=64*3

=192

now

a³b²c¹d

=(2³4²10 15)

=(8*16*10*15)

=120*16*10

=1200*16

=19200

8 0
3 years ago
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Sam opened a money-market account that pays 3% simple interest. He started the account with $7,000 and made no further deposits.
jeka94
T = (1/0.03) [(8050/7000)-1]
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3 years ago
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In the figure shown, r || s. If the measure of ∠ 2 = 146°, what is the measure of ∠ 7
borishaifa [10]

Answer:

34°

Step-by-step explanation:

1. First, let's find the measure of ∠1 because since r || s, that means ∠1 = ∠7 because they're both alternate exterior angles. Alternate exterior angles are congruent.

2. (Solving for ∠1)

  • 146 + x = 180
  • 146 + x - 146 = 180 - 146
  • x = 34

3. Now, since we know ∠1 = ∠7, ∠7 = 34°.

3 0
2 years ago
Y varies directly as x if y is 2 when x is 8 then the constant of variation is 1/4
sp2606 [1]

Answer:

a. True.

Step-by-step explanation:

y = kx

y = 2 when x = 8 gives:

2 = 8 * k

k = 2/8 = 1/4.

6 0
3 years ago
In parallelogram QRST QS RT Is QRST a rectangle ?
fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

RT=QS         (Diagonals)

QR=QR         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

\angle R=\angle Q

Since the sum of two consecutive angles of a parallelogram is 180 degree.

\angle R+\angle Q=180

2\angle R=180

\angle R=90

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

RT=QS         (Diagonals)

ST=ST         (Common side)

QT=RS         (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

\angle S=\angle T

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST  is a rectangle.

6 0
4 years ago
Read 2 more answers
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