If h is m above the ocean and your trying to find when the rocket reaches that ocean… as the function gives the height above the ocean at a given time, when the height equals 0 the rocket will have reached the ocean so solve for t when h=0. working out in the photo. i got t=48.88seconds
<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>
Answer:
lol don't listen to him/her, they're wrong.
it's 0.92, for plato. i got it right
Step-by-step explanation:
The depth of the bottom of the hole after the second day is 36 feet using addition operation.
<h3>What is addition?</h3>
In math, addition is the process of adding two or more integers together. Addends are the numbers that are added, while the sum refers to the outcome of the operation.
Given the depth on the first day is 26 ½ feet.
Depth on the second day = 9½ feet more than on the first day i.e. 9½ feet + depth on the first day
This implies, depth on the second day = 9½ + 26 ½
= 36 feet
Therefore, the depth of the bottom of the hole after the second day is 36 feet.
To learn more about addition, visit:
brainly.com/question/25621604
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