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2 years ago

What is 8,000,000,60,0000,53 expanded form

1 answer:

7 0

8,(14 Zeros after)+
6, (7 Zeros after)+
50+
3
so.
800000000000000+
60000000+
50+3
im not good with placing the commas though

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Julia asked to evaluate the expression four to the power of -3 before she can join her classmates outside. She decides to use th

vesna_86 [32]

Negative exponents work like this:

$a^{-b}=\dfrac{1}{a^b}$

So, you have

$4^{-3}=\dfrac{1}{4^3}=\dfrac{1}{64}$

This number is less than 1, so she will play tennis.

3 0

2 years ago

Jacob is a construction worker who earns a yearly Income given by the expression 2000x + 6000, where X is the number of

satela [25.4K]

Answer:

Answer:

The manager's prediction is false

Step-by-step explanation:

Given

Jacob: 2000x + 4000

Carlos: 3500x - 40000

Required

Determine if both expression will be the same if x = 35

To do this;

Equate both expressions and then solve for x

i.e.

2000x+4000=3500x-40000

Collect Like Terms

2000x+4000=3500x-40000

-1500x=-44000

Divide both sides by -1500

$\frac{-1500}{-1500} = \frac{-44000}{-1500} \\= \frac{-44000}{-1500}\\x= -29.3$

Hence, the manager's prediction is not true because x $\neq$ 35

7 0

2 years ago

Estimate the solution to the following system of equations by graphing.

zmey [24]

x=−1/2 and y=3/4 hope this helps.

3 0

2 years ago

Plz help me and give me the answer

enot [183]

Answer:

i think its the second option

Step-by-step explanation:

7 0

2 years ago

A simple random sample of 85 students is taken from a large university on the West Coast to estimate the proportion of students

ahrayia [7]

Answer:

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

Step-by-step explanation:

Step(i):-

Given that the sample size 'n' = 85

The sample proportion

$p = \frac{x}{n} = \frac{51}{85} = 0.6$

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

$(p^{-} -Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p(1-p)}{n} })$

Step(ii):-

Given that the level of significance

α = 0.05

Z₀.₀₅ = 1.96

$(0.6 -1.96 \sqrt{\frac{06(1-06)}{85} } , 0.6 +1.96 \sqrt{\frac{0.6(1-0.6)}{85} })$

(0.6 - 0.104138 , 0.6 +0.104138)

(0.4958 , 0.7041)

Final answer:-

95% confidence interval for p, the population proportion of students whose parents bought a car for them when they left for college

(0.4958 , 0.7041)

6 0

2 years ago