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Shkiper50 [21]
3 years ago
11

Mr. Jackson lengthened the fence along the back of his yard. Before he added 110 feet, the fence was 275 feet long. He divided t

he fence into 5-foot sections. How many 5-foot sections does he have now? A. 55 B. 22 C. 77 D. 385
Mathematics
1 answer:
kupik [55]3 years ago
4 0
C. 77 (You add 10 feet to the initial 275 feet giving you 385. Then you divide 385 by 5 in order to figure out how many 5 foot setions there are now)
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Use 1% or 10% to estimate 93% of 149<br><br> A. 169.5<br> B. 13.5<br> C. 112<br> D. 135
irakobra [83]
93% of 149

10% of 149 = 14,9

93% of 149 > 90% of 149

93% of 149 > 149 - 14,9 ≈ 149-15≈134
                   > 134
⇒ the answer is D

5 0
3 years ago
1) Ethan put $700 into a Certificate of Deposit (CD) account that earns 1.8% interest each year. What will the interest of the C
Inga [223]

Answer:

The interest After 6 years is $ 79.03  

Step-by-step explanation:

Given as :

The principal amount deposited in account = $ 700

The rate interest earn = 1.8 % per year

The Time period = 6 years

<u>From Compounded Method </u>

Amount = Principal × (1 +\dfrac{\textrm Rate}{100})^{\textrm Time

Or, Amount = $ 700 × (1 +\dfrac{\textrm 1.8}{100})^{\textrm 6

Or, Amount =  $ 700 × 1.018^{6}

Or, Amount =  $ 700 × 1.1129

∴ Amount = $ 779.03

Now , Interest = Amount - Principal

I.e Interest = $ 779.03 - $ 700 = $ 79.03

Hence The interest After 6 years is $ 79.03  ,  Answer

7 0
3 years ago
Read 2 more answers
I need to know the answer
makkiz [27]

Step-by-step explanation:

3k + 2k - 6 = 8k + 3

8k - 3k - 2k = - 6 - 3

8k - 5k = -9

3k = - 9

k = - 9/ 3

K = - 3

Hope it will help you :)

3 0
3 years ago
Read 2 more answers
For trapezoid JKLM, A and B are midpoints of the legs. Find AB.
romanna [79]

Answer:

29

Step-by-step explanation:

The length of the median of a trapezoid equals one-half the sum of the lengths of the bases.

\begin{array}{rcl}AB & = & \frac{1}{2}(JK + LM)\\\\& = & \frac{1}{2}(19 + 39)\\\\& = & \frac{1}{2}\times 58\\\\& = & \mathbf{29}\\\end{array}

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cint%7B%5Bsin%289x%29cos%289x%29%5D%7D%20%5C%2C%20dx" id="TexFormula1" title="\int{[sin(9x)c
Sladkaya [172]

Recall the double angle identity,

sin(2x) = 2 sin(x) cos(x)

Then we can write

sin(9x) cos(9x) = 1/2 sin(2 • 9x) = 1/2 sin(18x)

Then

∫ sin(9x) cos(9x) dx

= 1/2 ∫ sin(18x) dx

= -1/2 • 1/18 cos(18x) + C

= -1/36 cos(18x) + C

though you could continue with another double angle identity,

cos(2x) = cos²(x) - sin²(x)

to rewrite the antiderivative as

= -1/36 (cos²(9x) - sin²(9x)) + C

= 1/36 (sin²(9x) - cos²(9x)) + C

5 0
2 years ago
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