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FrozenT [24]
3 years ago
12

I need to know the answer

Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0

Answer:

k = - 3

Step-by-step explanation:

3k + 2k - 6 = 8k + 3 \\ 5k - 6 = 8k + 3 \\ 5k - 8k = 6 + 3 \\  - 3k = 9 \\ k =  \frac{9}{ - 3}  \\ \huge \red{ \boxed{ k =  - 3}}

makkiz [27]3 years ago
3 0

Step-by-step explanation:

3k + 2k - 6 = 8k + 3

8k - 3k - 2k = - 6 - 3

8k - 5k = -9

3k = - 9

k = - 9/ 3

K = - 3

Hope it will help you :)

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PLEASE HELP ANSWER ASAP
Solnce55 [7]

I cant help you on this if there is no coefficients.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B28%20%7D%20%20%2B%20%20%5Csqrt%7B343%7D%20%20%5Cdiv%202%20%5Csqrt%7B63%20%7D%20"
Nadusha1986 [10]

Answer:

Step-by-step explanation:

sqrt(28): sqrt(4*7)

sqrt(4) = 2;

sqrt28)=2*sqrt(7)

sqrt(343): sqrt(7 * 7 * 7) = 7 * sqrt(7)

Note: the rule is if you have 3 equal primes under the root sign, you leave one, you throw one away, and you put one outside the root sign.

2 sqrt(63) = 2 sqrt(3*3*7)  The above rule gets modified to throw 1 three away and take the other one outside the root sign.

2sqrt(63) = 2*3 sqrt(7)

Numerator: 2*sqrt(7) + 7sqrt(7) = 9sqrt(7)

9sqrt(7)

======

6 sqrt(7)

3/2

Note without brackets I cannot be certain that I have interpreted this correctly. The division only apply to sqrt(343) / 2 sqrt(63). If this is so please leave a note.

7 0
3 years ago
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