All categories

3 years ago

URGENT <------(cliched but true)

Mathematics

1 answer:

Oksana_A [137]3 years ago

3 0

A. If you draw the graphs you will find that B, C and D are all false.

You might be interested in

Solve the equation for x

PIT_PIT [208]

Answer:

$\bold{x=\frac{-6+z}6=-1+\frac z6}$

Step-by-step explanation:

$\bold{x-6+5x=-12+z}\\{}\quad +6\qquad\quad\ +6\\{\quad}\bold{6x\ =\ -6+z}\\{}\quad\div6\quad\ \ \div6\\{}\quad \bold{x=\frac{-6+z}6=-1+\frac z6}$

7 0

3 years ago

Which expression is equivalent to 2(3x − 1.75) − 3(1.5x − 2.5)?

lara [203]

Answer:

1.5x+4

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

GOOD AT MATH!! PLEASE HELPPP

Valentin [98]

It’s B I’m pretty sure

8 0

3 years ago

Read 2 more answers

Help please Math problems?

Andrews [41]

The answer is ep I think

3 0

4 years ago

Read 2 more answers

Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit

Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is $2$

Part 2) The vertex is the point $(1,8)$

Part 3) The equation of the axis of symmetry is $x=1$

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is $y=2x^{2}-4x+10$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

$x=h$

In this problem we have

$y=2(x-1)^{2}+8$ -----> this is the equation in vertex form of a vertical parabola

The value of $a=2$

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point $(1,8)$

$(h,k)=(1,8)$

The equation of the axis of symmetry is $x=1$

The equation of a vertical parabola in standard form is equal to

$y=ax^{2}+bx+c$

Convert vertex form in standard form

$y=2(x-1)^{2}+8$

$y=2(x^{2}-2x+1)+8$

$y=2x^{2}-4x+2+8$

$y=2x^{2}-4x+10$

see the attached figure to better understand the problem

7 0

3 years ago