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Virty [35]
3 years ago
9

Х+y=4 Find the value of y

Mathematics
2 answers:
ololo11 [35]3 years ago
7 0
X=y+4 the value is 4
satela [25.4K]3 years ago
6 0

Answer:

x=−y+4

Step-by-step explanation:

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Hunter-Best [27]
6 because 25%=1/4 of a number, and 6x4=24. So 1/4 or 25% of 24 is 6
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3 years ago
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Only answer this if you have an explanation and if you know what the answer is.
Klio2033 [76]

Answer:

G

Step-by-step explanation:

Since there are 50 students being asked, to find a percentage, put the output (the number of students that chose each genre) and the input (the number of students asked all together) in ratio form as a fraction. You will get the fractions 10/50, 16/50, 20/50, and 4/50. Multiply each denominator by two to get the percentage. You will get 20/100, 32,/100, 40/100, and 8/100. If you look at the four answers provided, you can cross out J immediately because it shows that "Other" was the greatest percentage, when it is in fact the smallest. H can be crossed out as well, since the percentage for "Mystery" is over 20% when it should be exactly at 20%. F can be crossed out as well because it shows that "Other" takes up 10%, when it is actually a bit less, 8%. G is the best choice because the percentage that "Other" takes up is a bit less than 10%, so it's safe to say that it shows 8%.

8 0
3 years ago
Square root of 512m^3. show work
ElenaW [278]

The solution would be like this for this specific problem:

√512m³ = √256m² × √2m

= 16 × √2m

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0
3 years ago
:)Which number line best shows how to solve -4 -(-6)?
Readme [11.4K]

Answer:

i dont see a # line..

Step-by-step explanation:

hmm hmm

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3 years ago
He variable y is directly proportional to the variable x . If y = 10 when x = 6, what is the value of y when x = 15?
Delicious77 [7]

Answer:

B. 25

Step-by-step explanation:

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if it is proportional, then it would be 25 to get 15.

4 0
3 years ago
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