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3 years ago

QUICK plzzzz. Don’t worry about the other questions just plz answer 17 for me :)

Mathematics

1 answer:

Eddi Din [679]3 years ago

5 0

Answer:

a) Vf = at + Vi

b) 10 m/s

Step-by-step explanation:

Part A:

first bring the t to the other side, when doing this the t will become a numerator: at= Vf-Vi

now bring the Vi over to the other side and flip the sign: at + Vi = Vf

this can be rewritten as Vf = at + Vi

Part B:

substitute the numbers: Vf = (2)(3) + 4

solve to get: Vf = 10 m/s

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Addison is making Caramel apples. She has 2 1/2 bags of apples. One bag has 8 apples, and each apple weighs 5 ounces

andrey2020 [161]

Answer:

The expression that can be used is :

Number of bags x Number of apples in a bag x Weight of 1 apple

The total weight of apples in 2 1/2 bags of apples = 100 ounces.

Step-by-step explanation:

The given question is INCOMPLETE.

Addison is making caramel apples. She has 2 1/2 bags of apples. One full bag has 8 apples, and each apple weighs 5 ounces. Write an expression that could be used to find the total number of ounces of apples Addison has. Then find the total number of ounces.

Now, here the weight of 1 apple = 5 ounces

1 bag = 8 apples

⇒ Weight of 8 apples = 8 x ( weight of 1 apple) = 8 x (5 oz) = 40 oz

⇒ Total weight of 1 bag of apples = 40 oz

Now, the total bags of Apples Addison has = 2 1/2 bag

= 2 + 1/2 bag = 2. 5 bag

So, the weight of apples in 2.5 such bags = 2.5 x ( Weight in 1 bag)

= 2.5 ( 40 oz) = 100 oz

Hence, the total weight of apples in 2 1/2 bag = 100 ounces.

The expression that can be used

= Number of bags x Number of apples in a bag x Weight of 1 apple

= 2 1/2 x 8 x (5 oz)

3 0

4 years ago

Suppose that two teams are playing a series of games, each of which is independently won by team A with probability p and by tea

Lady_Fox [76]

Answer:

4 games played = 1/56

5 games played = 5/56

6 games played = 15/56

7 games played = 35/56

Step-by-step explanation:

The probability of each time winning is 0.5

So there are a couple of ways the series could go.

Team A could win all first 4 matches. We can depict this as A-A-A-A
Team A could win 4, while having lost 1. Lets depict this a A-B-A-A-A
Team A could win 4, while having lost 2. A-B-B-A-A-A
Team A could win 4, while having lost 3. A-B-B-B-A-A-A

These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.

I advise you to study 'how to permute identical objects' for this.

These permutations are stated below:

1. 4!/4! = 1

2. $\frac{5!}{4! * 1!}$ = 5