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OLga [1]
3 years ago
9

Did the Native Americans The pilgrims encountered lived in tipis and traveled on horseback?

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0
<span>Answer: The fields Indians lived in tipis. Indians in New England would have solidified to death in tipis. Furthermore, obviously stallions are not indigenous to the New World, so Indians didn't have them until the point that the White Man brought them. In any case, the Pilgrims were not the main Europeans in the New World, by any extend of the creative ability, so it's conceivable a few Indians had stallions by at that point. When we think about the word 'Indian' we promptly get a photo of a fields Indian, the Sioux or the Lakota. I think this is generally a direct result of our extraordinary legacy of western motion pictures about cowhands and Indians. The Indians on the East Coast were altogether different from that photo of buckskins, interlaces, plumes in the hair, and so on. The entire story of the Pilgrims is covered in myth and false history. For a certain something, they weren't generally Pilgrims. They weren't even truly Puritans! They were a chip assemble from the standard Puritan people group, calling themselves 'Precisionists'. They didn't come here to build up a group of religious opportunity, however one that they could keep running by their own particular religion. They didn't put stock in the partition of chapel and state (as our establishing fathers did), they trusted the congregation WAS the state. In any case, at that point a considerable measure of the American history we learn in primary school and secondary school is this way, more a teaching than an instruction. When you examine American history in school you need to unlearn all you've been shown up until this point.</span>
aleksley [76]3 years ago
3 0

Answer:

They were nomadic and moved from place to place.

Step-by-step explanation:

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List all the composit numbers between 1-10
torisob [31]
The answer is 4, 6, 8, 9, and 10. The following numbers (1, 2, 3, 5, and 7) are prime numbers.
6 0
3 years ago
Solve the equation
Vikki [24]

Answer:

x ≈ - 5.32, x ≈ 1.32

Step-by-step explanation:

Given

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± \sqrt{11} ( subtract 2 from both sides )

x = - 2 ± \sqrt{11}

Thus

x = - 2 - \sqrt{11} ≈ - 5.32 ( to 2 dec. places )

x = - 2 + \sqrt{11} ≈ 1.32 ( to 2 dec. places )

4 0
3 years ago
In one version of trail mix, there are 3 cups of peanuts mixed with 2 cups of raisins. In another version of trail mix, there ar
vagabundo [1.1K]

Answer:

No

Step-by-step explanation:

The 4.5 cups of peanuts should be 4

3 0
3 years ago
Write an equation for a line parallel to y=-3x-5 and passing through the point (4,-16)
const2013 [10]

Answer:

Insert the numbers into the equation y=3x-5.

the rule states that in every equation the first number is x.so it will be -6=3(4)-5

-6=12-5

-6=7.

If u want, you can leave your answer like that

3 0
3 years ago
HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️
Rainbow [258]

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

3 0
2 years ago
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