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skad [1K]
3 years ago
12

Calculate the average rate of change for the given graph from x = –2 to x = 0 and select the correct answer below.

Mathematics
1 answer:
telo118 [61]3 years ago
3 0
We need to find f(x) on those 2 points and than divide y length (f(x2)-f(x1)) with x lenght (x2 - x1) to find average

f(x = -2) = 0

f(x = 0) = 6

Avg = 6 / 2 = 3

Answer is C

We have to use absolute valuee for x distance because distance between x1 and x2 cannot be negative it can only be positive.
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The radius of the Ferris wheel is shown. Which is the circumference of the Ferris
yulyashka [42]
The answer is c=250 feet because the circumference is twice the radio us I’m pretty sure.
4 0
3 years ago
Read 2 more answers
Show how to make ten to solve 13-7. Write in a number sentence. _-_-_-_-_=_
ser-zykov [4K]

Answer: The answer is 6.

The number sentence is

3-3=0

10-4=6

So, 13-7=6

Step-by-step explanation:

To solve 13-7, by making ten

First break 13 and write 13=10+3

Then break 7 as 7=3+4

Now to subtract 7 from 13,

Step 1. Subtract 3 (a part of 7), from 3(a part of 13) or cross 3 circles, then we have left 10-4

13-7=10+3-(3+4)=10+3-3-4=10-4

Step 2. Subtract 4 from 10 or cross 4 circles out of 10, we get 6.

The answer is 6.

5 0
3 years ago
Read 2 more answers
Doña Gertrudis recolecta en promedio 75 litros de leche de cabra por día y utiliza alrededor de 5 litros para hacer un kilogramo
Nimfa-mama [501]

Answer:

825 pesos a day on average

1 dozen weight = 2.4 kg

Step-by-step explanation:

In ENGLISH:

Doña Gertrudis collects on average 75 liters of goat milk per day and uses around 5 liters to make one kilogram of cheese. The cheeses he makes weigh 200 grams each and he sells them for 132 pesos a dozen. How much money do you get per day on average from the sale of your cheeses? How many kilograms does the dozen cheeses weigh?

<u>Solution:</u>

75 Liters / 5 Liters = 15

15 * 1 kg = 15 kg of cheese per day

15kg in grams is 15*1000 = 15,000 grams

Each cheese block is 200 grams, so number of blocks of cheese:

15,000/200 = 75 blocks of cheese

1 dozen (12) = 132 pesos, so 1 would be:

132/12 = 11 pesos PER BLOCK

SO, 75 blocks of cheese = 75 * 11 = <u>825 pesos (per day on average)</u>

<u></u>

Dozen cheese weight in kg,

200 grams * 12 = 2400 grams

In kg,

2400/1000 = <u>2.4 kg</u>

8 0
3 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
What is the value of x? Enter your answer in the box.
mario62 [17]
X = 12

because if you notice, each of the angles have a little arc in the corner, which means they are congruent. if all three angles are congruent, that means each angle is 60° because each triangle has a maximum value of 180°. therefore, this means it is an equilateral triangle.

that being said, each side must be equal as well. so, you can use any two sides to find x by using each one on a different side of an equation, then isolating and solving.

5x - 22 = 3x + 2 = 4x - 10

so

5x - 22 = 3x + 2
3x + 2 = 4x - 10
4x - 10 = 5x - 22

whichever one you solve for, x = 12. and if you plug in that number for x, each side equals the same number = 38
8 0
3 years ago
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