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3 years ago

7

Anyone have any idea wut the answer is bec I cant figure it out

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

t=d/r

Step-by-step explanation:

d=rt we take r to d

which is t=d/r

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In this diagram, BAC – EDF. If the

puteri [66]

The triangles are congruent. So.

Triangle ABC is 24 inch^2 and BC is 4 inches.
The area of a triangle is 0.5 x base x height. The will be 12 because 12 x 4 x 0.5 which equals 24.

Triangle DEF is half the size of ABC because bc is 4 and EF is 2 showing it’s half. This then means the height will be half which then mean it will be 6.

This then means we can use the equation to work it out. So. 6 x 0.5 x 2 = 6in^2

The answer is 6inches^2

6 0

2 years ago

Heklp me again please if you dont mind

matrenka [14]

Step-by-step explanation:

This is the answer of this question.

4 0

3 years ago

Someone help me plz !!!!!

Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

$\frac{40}{1000} = \frac{1}{x}$

so, X=25

x = What we want to find

4 0

2 years ago

Explain how to do this

Lera25 [3.4K]

Average of 2 numbers is 40
so total = 2 x 40 = 80

300 - 80 = 220

average of remaining 10 numbers = 220/10 = 22

answer
B) 22

6 0

3 years ago

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0

2 years ago