Answer:
a.) one sample t test
b.) H0 : μ = 59.3
c.) H1 : μ > 59.3
d.) μ = 59.3 ; σ = 39.84
e.) xbar = 79.4 ; s = 61.36
Test statistic = 3.16
Step-by-step explanation:
Given the sample data:
49.00 49.00 49.00 49.00 49.00 63.00 63.00 63.00 63.00 63.00 199.00 199.00 199.00 199.00 199.00 38.00 38.00 38.00 38.00 38.00 48.00 48.00 48.00 48.00 48.00 49.00 63.00 199.00 38.00 48.00
Sample size, n = 30
Using calculator :
xbar from the data above = 79.4
Standard deviation = 61.359
H0 : μ = 59.3
H1 : μ > 59.3
Test statistic :
(Xbar - μ) ÷ (σ/sqrt(n)
σ = 34.83
(79.4 - 59.3) ÷ (34.83/sqrt(30))
20.1 ÷ 6.359
Test statistic = 3.16
The answer is 2.99 explanation is that I used my calculator lol
Answer:
Step-by-step explanation:
x = the number
x + 1/6x + 2 1/2x + 7 = 12 1/2
3 + (1/6 + 1/2)x = 12 1/2 - 7
3 + (1/6 + 3/6)x = 5 1/2
3 2/3x = 5 1/2
x = (11/2) / (11/3)
x = 11 / 2 * 3 / 11
x = 3/2
x = 1 1/2
Answer:
C
15 + x
Step by step explanation
For Company X, the initial cost is 30 cents plus 5 cents per minute, so the expression would be 30 + 5x (x would represent minutes.
For Company Y, the initial cost is 15 cents plus 4 cents per minute, so the expression would be 15 + 4x (x would represent minutes.)
Then subtract the expression of Y from the expression of X to show the difference in value between Y and X.
So, 30 + 5x - (15 +4x)
Distribute the subtraction sign.
30 + 5x - 15 - 4x
Solve across.
15 + x