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Anna71 [15]
3 years ago
9

The annual Gross Domestic Product (GDP) of a country is the value of all of the goods and services produced in the country durin

g a year. During the period 1985-1999, the Gross Domestic Product of the United States grew about 3.2% per year, measured in 1996 dollars. In 1985, the GDP was $577 billion. I what year did/or will the GDP equal $1.6 trillion?
Mathematics
1 answer:
lawyer [7]3 years ago
5 0
The increase indicates a compound growth of 3.2% per year.
The multiplier is given by 100%+3.2% = 103.2% = 1.032

The initial amount of GDP is 577 billion

We are looking to find in how many years since 1985 that the GDP equals to 1.6 trillion, this is  1.6×10³ billion

The formula for a compound growth/decay is given as
A_{n}= A_{o} (Multiplier)^{n}, where A_{n} is the final value and  A_{o} is the intial value.

We are looking to find 'n'

1.6×10³ = 577(1.032)ⁿ
(1.6×10³) ÷ 577 = 1.032ⁿ
1060/577 = 1.032ⁿ ⇒ take log both sides
log( 1060/577 ) = log (1.032)ⁿ
log (1060/577) ÷ log (1.032) = n
n = 19.31 ≈ 19 years

The year when GDP achieves 1.6 trillion is 19 years from 1985, which will be in 2004, providing the increase rates stays the same.
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astra-53 [7]

Answer:

x \leqslant 1

Step-by-step explanation:

first multiply both side by 2 to get rid of the fraction

3x + 5 \leqslant 4(2)

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2 years ago
bill js a builder. On Monday he msde mortar mix. he used 24kg of sand and 5kg of cement. on tuesday bill will make the same type
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Answer: 7.5kg

Step-by-step explanation:

Since Bill made mortar mix and he used 24kg of sand and 5kg of cement. This means that for 1 kg of cement, (24/5) = 4.8 kg of sand is used.

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5 0
2 years ago
Write a formula for the world population and sketch the graph. In 2007, the world's population reached 6.7 billion was increasin
NeX [460]
<span>in 2007, the world's population reached 6.7 billion was increasing at a rate of 1.2% per year. Assume that the growth rate remains constant.

Generalize the expression for the world's population for t years since 2007 is:</span> <span>P(t) = 6,700,000 (1.012)^t </span>
4 0
3 years ago
The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the m
Amanda [17]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Assum a normal distribution :

Mean (m) = 140 mm

Standard deviation (sd) = 20 mm

The percentage of people with blood pressure between 115 and 165 mm.

Zscore = (x - m) / sd

X = 115 mm

(115 - 140) / 20

-25/20 = - 0.625 = - 0.63

P(z<-0.63) = 0.2643

X = 165 mm

(165 - 140) / 20

25/20 = 0.625 = 0.63

P(z< 0.63) = 0.7357

0.7357 - 0.2643 = 0.4714 = 47.14%

B.) The percentage of people with blood pressure between 140 and 165 mm.

Zscore = (x - m) / sd

X = 140 mm

(140 - 140) / 20

0/20 = 0 = 0

P(z<0) = 0.5000

X = 165 mm

(165 - 140) / 20

25/20 = 0.625 = 0.63

P(z< 0.63) = 0.7357

0.7357 - 0.5000 = 0.2357 = 23.57%

C.) ___ The percentage of people with blood pressure over 165 mm.

X = 165mm

(165 - 140) / 20

25/20 = 0.625 = 0.63

1 - P(z< 0.63) = 0.7357

1 - 0.7357 = 0.2643 * 100% = 26.43%

8 0
3 years ago
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