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PolarNik [594]
3 years ago
6

A model airplane is shot up from a platform 1 foot above the ground with an initial upward velocity of 56 feet per second. The h

ight of the airplane above ground after t seconds is given by the equation h=-16t^2+56t+1 where h is the hight of the airplane in feet and t is the time in seconds after it is launched. Approximately how long does it take the airplane to reach its maximum height?
A)0.3 seconds
B)1.8 seconds
C)3.5 seconds
D)6.9 seconds
Please Help
Mathematics
2 answers:
docker41 [41]3 years ago
8 0

Answer:

The correct answer is B. 1.8 seconds. I just took the test!


Law Incorporation [45]3 years ago
4 0
H=-16t^2+56t+1, the airplane is shot up from a platform 1 foot above the ground, so 1= - 16t^2+56t+1, we solve this equation
(- 16t+56)t=0, (- 16t+56)=0 or t=o, - 16t+56=0, implies t =3.5s
so the answer is C)3.5 seconds 
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6 0
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Suppose that 21 inches of wire costs 63 cents.
defon

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162 cents

Step-by-step explanation:

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6 0
2 years ago
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egoroff_w [7]
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recall what exponents mean

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so we cannot add exponents for 12³*11³ because that means 12*12*12*11*11*11
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or you  could refer to the rule
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notice when x=x then we can add the bases


fun fact below
we can reverse a previous exponential rule like this
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therefor
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