A triangle has a base that is increasing at a rate of 18 mm per minute with the height being held constant. What is the rate of
change of the area of the triangle if the height is 7 mm
1 answer:
Answer:
<h2>
63mm/min</h2>
Step-by-step explanation:
Area of a triangle = 1/2 * base * height
A = 1/2bh
Rate of change of area is expresssed as dA/dt = dA/db * db/bt
db/dt is the rate at which the base is increasing.
Given db/dt = 18mm/min
A = 1/2*7b
A = 7b/2
dA/db = 7/2
The rate at which the area is changing dA/dt = dA/db * db/bt
dA/dt = 7/2 * 18
dA/dt = 7*9
dA/dt = 63mm/min
<em>Hence the rate at which the area of the triangle is changing is 63mm/min </em>
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