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olasank [31]
2 years ago
11

Please help me i dont know what i am doing

Mathematics
1 answer:
Olenka [21]2 years ago
8 0

Answer:

  1. answer is 1.25
  2. 90

<h2>Step-by-step explanation:</h2><h2 />

<u>i</u><u> </u><u>h</u><u>o</u><u>p</u><u>e</u><u> </u><u>i</u><u>t</u><u>s</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u> </u><u>y</u><u>o</u><u>u</u>

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a rhombus as an area of 72 ft and the product of the diagonals is 144. What is the length of each diagonal?
SashulF [63]

A = (1/2)(x)(y)

Let x = diagonal 1

Let y = diagonal 2

The product of xy = 144.

This means that x = 12 and y = 12.

So, 12 • 12 = 144

Each diagonal is 12 feet.

Prove:

72 feet = (1/2)(12)(12) feet

72 feet = (1/2)(144) feet

72 feet = 72 feet

6 0
3 years ago
If g( n ) = 3 n - 2, then what is the value of g(10)?<br><br> 4<br> 28<br> 308<br> 24
tino4ka555 [31]

Answer:

28

Step-by-step explanation:

g(10)=3n-2

10=n

3(10)-2

REMEMBER PEMDAS

Parentheses, Exponent, Multiplication, Division, Addition, and Subtraction.

3(10)=30

30-2=28

Hope this helps have a wonderful evening!

8 0
2 years ago
A cone has a diameter of 6 cm and a height of 11.5 cm. Find the volume. Round your answer to the nearest 10th if necessary. Use
uysha [10]
V=πr^2h/3=π·3^2·11.5/3≈108.38495 or 108.40 rounded
5 0
2 years ago
A 250 m train travels through a 2km tunnel at 27 km/hr. How long is it from the time the front of the train enters the tunnel, t
olga55 [171]

Answer:

5 min

Step-by-step explanation:

time taken=distance required to travel/speed of train

total distance train have to cover to just left the tunnel is (lenght of tunnel+length of train) =2km+250m

=2250m

speed of train is 27km/hr

multiply 5/18 to convert in m/s

i.e, (5/18)×27=7.5m/s

now time taken =2250m/(7.5m/s)

=300s

and,300s =5min

4 0
3 years ago
For some value of z, the value of the cumulative standardized normal distribution is 0.8340. the value of z is
Aleksandr-060686 [28]

For some value of z, the value of the cumulative standardized normal distribution is 0.8340. the value of z is

Answer: We are required to find the value of z corresponding to probability 0.8340.

i.e., P(Z

We can find the value of z using the standard normal table.

Using the standard normal table, we have:

z(0.8340)=0.97

Therefore, for the value of z = 0.97, cumulative standardized normal distribution is 0.8340

Attached here standard normal table for your reference.



6 0
3 years ago
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