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strojnjashka [21]
3 years ago
12

The area of a rectangle is 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same are b

ut a different perimeter. Is the second rectangle a square?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0
The second one would be a square
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andres has 4 bunches of balloons. there are 6 balloons in each bunchs how many balloons does andres have in all
Whitepunk [10]

\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}

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\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}

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  • <em>To</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>4</em><em> </em><em>bunches</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>bumber</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>bunch</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>bunches</em><em>.</em>

\tt\multimap \: number \: of \: balloons \: in \: 1 \: bunch \times number \: of \: bunches

\sf \nrightarrow \: 6 \times 4 = 24

➪ <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>2</em><em>4</em><em> </em><em>b</em><em>a</em><em>l</em><em>l</em><em>o</em><em>o</em><em>n</em><em>s</em><em> </em><em>i</em><em>n</em><em> </em><em>4</em><em> </em><em>b</em><em>u</em><em>n</em><em>c</em><em>h</em><em>e</em><em>s</em><em>.</em><em>.</em><em>.</em><em>~</em>

8 0
2 years ago
Read 2 more answers
I have a two digit number the sum of the digits is 12 the first digit is 4 Less Than 3 times the second what is my number​
nignag [31]

Answer:

84

Step-by-step explanation:

Let the first digit = x

Let the second digit =y

x + y = 12

x + 4 = 3*y

===========

From the second equation, we learn that x = 3y - 4

Put that into the first equation.

3y - 4 + y = 12          Combine the left side

4y - 4 = 12                Add 4 to both sides

4y = 16                     Divide by 4

4y/4 = 16/4        

y = 4  

=================

x + 4 = 12

x + 4 - 4 = 12-4

x = 8

So the number is 84

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2 years ago
HELPPPPP PLZZZZ<br> What real number a and b make the equation true?<br> (a-3)+(b+8)i=3-4i
Radda [10]

Answer:

a= 6

b= -12

Step-by-step explanation:

In complex number algebra, you need to sum the real values with each others and the imaginary values with each others.

In order to determine which number is a real value and which one is an imaginary, we must expand the parenthesis terms:

(a-3) + (b+8)i =a - 3 + bi + 8i = 3 - 4i

Now we match real numbers with real numbers and imaginary numbers with imaginary numbers:

a - 3 = 3\\a= 3 - (-3) = 6\\\\b + 8 = -4 \\b= -4 -8 = -12\\

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2 years ago
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