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garik1379 [7]
3 years ago
6

Find a point on Y-axis which is equidistant from the points (2,-2) and (-4,2)

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

( -1, 0)

Step-by-step explanation:

(2 + -4)/2 = -1

(2 + -2)/2 = 0

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The length of a rectangle is 1 meter more than twice the width. If the area of the rectangle is 36 m, find the length and the wi
stepladder [879]

Answer:4th answer

Step-by-step explanation:

if width=w

Length =2w+1

Area =length *breadth

36=w(2w+1)

36=2w^2+w

0=2w^2+w-36

3 0
4 years ago
A pipe is leaking at the rate of 16 fluid ounces per minute. Use unit analysis to find out how many gallons the pipe is leaking
larisa [96]

Answer:

The answer is 7.5 gallons per hour.

Step-by-step explanation:

16 fluid ounces multiplied by 60 minutes equals 960 fluid ounces

16 * 60 = 960

960 fluid ounces divided by 128 fluid ounces (which is 1 gallon) equals 7.5 gallons.

960 / 128 + 7.5

So the answer is 7.5 gallons per hour.

Hope this helps! :)

3 0
2 years ago
Will give brainliest.
dolphi86 [110]

Answer:

Its a right isosceles triangle

4 0
2 years ago
Read 2 more answers
Suppose f(x) = x^2 and g(x) = (1/3x)^2. Which statement best compares the graph of g(x) with the graph of f(x)?
miv72 [106K]
Since it would be (1/3) squared, it would be a vertical compression of 9. since the x is not the output, it would make a horizontal stretch factor of 3.
5 0
3 years ago
Determine the total number of proper subsets of the set of letters from the English alphabet a,b, c, ...,j. The number of proper
Inga [223]
\{a,b,c,\ldots,j\} has ten elements, so any proper subset has at most nine of these elements.

The number of ways of taking any 0\le n\le 9 letters from this set is given by the binomial coefficient,

\dbinom{10}n=\dfrac{10!}{n!(10-n)!}

and in particular, the total number of ways to picking proper subsets is

\displaystyle\sum_{n=0}^9\binom{10}n=\dbinom{10}0+\dbinom{10}1+\cdots+\dbinom{10}9

Without computing each term directly, let's instead use a direct result from the binomial theorem, which says

\displaystyle\sum_{n=0}^N\binom Nna^nb^{N-n}=(a+b)^N

If we replace a=b=1, then we're left with

\displaystyle\sum_{n=0}^N\binom Nn=(1+1)^N=2^N

We can use this to evaluate our sum directly:

\displaystyle\sum_{n=0}^9\binom{10}n=\sum_{n=0}^{10}\binom{10}n-\binom{10}{10}=2^{10}-1=1023
8 0
3 years ago
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