Which of the following gives an example of a set that is closed under addition.

a man bought a motor at 400,000 Kenyan shillings in January 1999 it depreciated at a rate of 16% per annum if he value it six mo

Alexxx [7]

The value of the car is January 2003 is $199,148.54.

<h3>What is the value of the car?</h3>

Depreciation is the rate of decline in the value of an asset with the passage of time.

The exponential equation that can be used to determine the value of the car is:

Value of the car = purchase value(1 - rate of decline)^time

400,000 x (1 - 0.16)^(2003 - 1999)

400,000 x (0.84^4) = $199,148.54

To learn more about depreciation, please check: brainly.com/question/15085226

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8 0

1 year ago

ANswer please! Brainliest!!

andreyandreev [35.5K]

Answer:

b and c

Step-by-step explanation:

5 0

2 years ago

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

3 years ago

2. The water level in a reservoir is now 52 meters. Which equation can be used to find the initial depth, d, if this is the wate

Maru [420]

Answer:

1.23d = 52

Explanation:

If 52 meters is the water level after a 23% increase, then we can say that the initial depth d added to the 23% of d is equal to 52 meters. So:

d + 23%d = 52 meters

Since 23% is equivalent to 0.23, we get:

d + 0.23d = 52

Finally, adding the like terms, we get:

(1 + 0.23)d = 52

1.23d = 52

So, the equation is:

1.23d = 52

8 0

4 months ago

The distance between P and T on the coordinate grid is units. (Input whole numbers only.)

nlexa [21]

Answer:ummm do you have a picture of the question?

Step-by-step explanation:

7 0

2 years ago

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