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3 years ago

Which equations are true?

Mathematics

2 answers:

atroni [7]3 years ago

8 0

Answer:

The third one and the fourth one.

Step-by-step explanation:

61 x 5 = 305. Not 3050

381*27=10287. Not 1152

854*63=53802.

562*42=23604

72*30=2160. Not 270

Alexeev081 [22]3 years ago

6 0

Answer:

The third and fourth equations are true.

Step-by-step explanation:

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7 0

3 years ago

Someone please tell me the answers to this please I beg you

Wittaler [7]

1) 216
2) 203
3) 315
4) 256
5) 576
6) 440

7 0

3 years ago

Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.

lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

$PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ$

Likewise:

$\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ$

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

$m\angle PAC=m\angle PAB+m\angle BAC$

Likewise:

$m\angle QAB=m\angle QAC+m\angle BAC$

Since ∠QAC ≅ ∠PAB:

$m\angle PAC=m\angle QAC+m\angle BAC$

And by substitution:

$m\angle PAC=m\angle QAB$

Thus:

$\angle PAC\cong \angle QAB$

Then by SAS Congruence:

$\Delta PAC\cong \Delta BAQ$

And by CPCTC:

$PC\cong BQ$

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3 years ago

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yawa3891 [41]

Answer:

Step-by-step explanation:

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3 years ago

* WILL GIVE BRIANLIEST*(08.03)Consider the following set of equations:

cluponka [151]

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3 years ago

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