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abruzzese [7]
3 years ago
15

The length of a room is 23 1/2 feet. When using a 1/8 inch = 1 foot scale, find the length of

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

2.9375 inches or 2 15/16"

Step-by-step explanation:

23 1/2 feet equals 282 inches

(1/8 ÷ 12) = (x ÷ 282)

cross-multiply:

35.25 = 12x

x = 2.9375 or 2 15/16 inches

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No it is not. They are the wrong points
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Jackson wrote the equation below on the whiteboard.
faust18 [17]
B = 7

7 x 6 = 42

42 + 6 = 48.
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What is the y-intercept of the function, represented by the table of values below? x: -2,1,2,4,7 y: 14,8,6,2,-4
anastassius [24]

Answer:

The y-intercept is at y = 10.

Step-by-step explanation:

It will be between y = 14 and y = 7 because the corresponding x values are -2 and 1.

An increase of 3 units of x  gives a decrease of 6 units of y fro the above values.

Then an increase of 1 ( 1 to 2) in x gives decrease in y of 2 (8 to 6). The other values show the same pattern.

So very unit increase in x,  the y values change by -2.

So  from x = -2 to 0 is +2 units for x and this will be -4 units for y  so the y-intercept ( when x = 0) will be at y = 14-4 = 10

y-intercept  is (0,10).


7 0
3 years ago
Help ASAP please!!!
N76 [4]

Answer:

$450,000.

Step-by-step explanation:

<h3>100% - 38% = 62% of the previous house value is the current house value after the 38% decrease.</h3><h3>We'll first convert 62% to a decimal by dividing by 100.</h3>

62% = 62 / 100 = 0.62

<h2>0.62x = 279,000</h2><h3>Multiply by (100/62) on each side.</h3><h2>x = 450,000</h2><h2>The house value when it was purchased was $450,000.</h2>
8 0
3 years ago
Twenty different books are to be put on five book shelves, each of which holds at least twenty books.
olya-2409 [2.1K]

Answer:

(a) 10,626 different arrangements

(b) 95,367,431,640,625 different arrangements

(c) 2.5852017 × 10²² different arrangements

Step-by-step explanation:

(a) How many different arrangements are there if you only care about the number of books on the shelves (and not which book is where)?

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626 arrangements

(b) How many different arrangements are there if you care about which books are where, but the order of the books on the shelves doesn't matter?

Since the order of the books on the shelves does not matter,

The calculation is given as

5²⁰ = 95,367,431,640,625 arrangements

(c) How many different arrangements are there if the order on the shelves does matter?

Since order matters now

Step 1

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626

Step 2

We find the factorial of the number books

= 20!

= 2,432,902,008,176,640,000

Step 3

The different arrangements there are if the order on the shelves does matter is calculated

= 10,626 × 2,432,902,008,176,640,000

= 2.5852017 × 10²² different arrangements

8 0
3 years ago
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