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ra1l [238]
3 years ago
8

DE is parallel to XY what is x

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
X = 85

That is because 85 and x are alternate interior.

Hhope this helps :)
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I need help on 14 and 15.
Savatey [412]

Answer:

14  one   15  6

Step-by-step explanation:

6 0
3 years ago
The function y = f (x) is graphed below. What is the average rate of change of the function f(x) on the interval - 1 ≤ x ≤ 3?
jonny [76]

Answer:

\displaystyle -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Average Rate of Change: \displaystyle \frac{f(b) - f(a)}{b - a}

Step-by-step explanation:

<u>Step 1: Define</u>

Interval -1 ≤ x ≤ 3

a = -1, b = 3

f(a) = f(-1) = 4

f(b) = f(3) = -4

<u>Step 2: Find Average</u>

  1. Substitute in variables [ARC]:                     \displaystyle \frac{f(3) - f(-1)}{3 + 1}
  2. Substitute:                                                   \displaystyle \frac{-4 - 4}{3 + 1}
  3. [Fraction] Subtract/Add:                             \displaystyle \frac{-8}{4}
  4. [Fraction] Divide:                                        \displaystyle -2
4 0
2 years ago
Help me please <br> PLEASEEE
vodka [1.7K]
So you can do 1/2 and then divide it by 1/8.

To divide by a fraction, multiply by its reciprocal.
So;
1/2 / 1/8 = 1/2•8/1

1/2• 8 = 8/2
8/2= 4

So he can fill 4 mugs!!!

Brainliest if i helped!
7 0
3 years ago
Read 2 more answers
Select all possible values for x in the equation x^3=375?
Helga [31]
<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

<h2>Why?</h2>

To solve the problem, we need to remember the following properties of the exponents and roots:

a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}

Then, we are given the expression:

x^{3}=375

So, finding "x", we have:

x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}

Hence, the possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

Have a nice day!

7 0
3 years ago
A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

H_0 : \sigma = 10

H_1 : \sigma \neq 10

The test statistics can be computed as follows:

X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}

X^2 = \dfrac{(36 -1)10.1^2 }{10^2}

X^2 = \dfrac{(35)102.01 }{100}

X^2 = \dfrac{3570.35 }{100}

X^2 =35.704

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703      ( to four decimal places)

Decision Rule : To reject the null hypothesis if  P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

3 0
3 years ago
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